Answer:
y- intercept --> Location on graph where input is zero
f(x) < 0 --> Intervals of the domain where the graph is below the x-axis
x- intercept --> Location on graph where output is zero
f(x) > 0 --> Intervals of the domain where the graph is above the x-axis
Step-by-step explanation:
Y-intercept: The y-intercept is equivalent to the point where x= 0. 'x' is the input variable in an equation, therefore the y-intercept is where the input, or x, is equal to 0.
f(x) <0: Notice the 'lesser than' sign. This means that the value of f(x), or 'y', is less than 0. This means that this area consists of intervals of the domain below the x-axis.
X-intercept: The x-intercept is the location of the graph where y= 0, or the output is equal to 0.
f(x) >0: In this, there is a 'greater than' sign. This means that f(x), or 'y', is greater than 0. Therefore, this consists of intervals of the domain above the x-axis.
To solve for the area of the triangle
Use the formula 1/2(base *height)
1/2 * 17* 4
68/2
34
I believe the area of the triangle is therefore 34ft
Answer: option B
Step-by-step explanation:
-4, 1, 3
Answer:
- 225°
- quadrant 3
- reference angle of 45°
Step-by-step explanation:
585-360= 225
225° is in quad 3
reference angle for quad 3 is
225° - 180°
Given that the distance between two lines in the measurement instrument is 0.01m, the maximum error should be 0.01m/2 = 0.005 m.
If you do a good work, the real measure is 1.20m +/- 0.005m, this is between 1.195 and 1.205.
