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Verdich [7]
3 years ago
7

5 - 6 - 9 - 8 - 5 - 4 + 5 - 5 -5 -5 - 32 = ?

Mathematics
2 answers:
iris [78.8K]3 years ago
7 0

Answer:

-69

Step-by-step explanation:

ooooo that's an interesting number

musickatia [10]3 years ago
6 0

5 - 6 = -1

-1 - 9  = -10

-10 - 8 = -18

-18 - 5 = -23

-23 - 4  = -27

-27 + 5  = -22

-22 - 5 = -27

-27 -5 = -32

-32 -5  = -37

-37 - 32 = -69

Answer = -69

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Help please! Use the area to find the value of x:
olga55 [171]

Answer:

x = 6

Step-by-step explanation:

A = 1/2bh

36 = 1/2(12)(x)

x = 6

3 0
3 years ago
a baseball team paid eight times as much to their ace pitcher as they paid to their shortstop. if they paid 81 million for the t
GenaCL600 [577]

x +y = 81 million

 let x be the short stop and y be the pitcher

 so pitcher (y) gets 2 times what the the shortstop (x) gets so y = 2x

 so x + 2x = 81 million

3x = 81

x = 27

 the short stop makes 27 million

 the pitcher makes 54 million

7 0
3 years ago
here are some numbers 8 11 13 18 25 37 , 8 13 18 is an arithmetic progression and the rule is to add 5 use 3 of the numbers to m
chubhunter [2.5K]

Answer:

11, 18, 25

Step-by-step explanation:

add 7

3 0
3 years ago
Find two consecutive even numbers such that the difference of one-half the larger and two-fifths the smaller is equal to 38
expeople1 [14]
EXPLANATION

The consecutive even numbers are
370 \: and \: 372

EXPLANATION

Let
x
be the first even number then, the next even number will be,

x + 2

The difference of one-half the larger one and two-fifth the smaller one is 38 gives the equation,


\frac{1}{2} (x + 2) -  \frac{2}{5} x = 38


We multiply through with an LCM of 10 to get,



10 \times \frac{1}{2} (x + 2) - 10 \times  \frac{2}{5} x = 38 \times 10


This simplifies to,


5(x + 2) -  4x = 380


We expand the brackets to get,


5x + 10 - 4x = 380

We group like terms to get,


5x - 4x = 380 - 10



This simplifies to
x = 370

Therefore the next even number is is
372
6 0
3 years ago
Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that
FromTheMoon [43]

Answer:

The Taylor series is \ln(x) = \ln 3 + \sum_{n=1}^{\infty} (-1)^{n+1} \frac{(x-3)^n}{3^n n}.

The radius of convergence is R=3.

Step-by-step explanation:

<em>The Taylor expansion.</em>

Recall that as we want the Taylor series centered at a=3 its expression is given in powers of (x-3). With this in mind we need to do some transformations with the goal to obtain the asked Taylor series from the Taylor expansion of \ln(1+x).

Then,

\ln(x) = \ln(x-3+3) = \ln(3(\frac{x-3}{3} + 1 )) = \ln 3 + \ln(1 + \frac{x-3}{3}).

Now, in order to make a more compact notation write \frac{x-3}{3}=y. Thus, the above expression becomes

\ln(x) = \ln 3 + \ln(1+y).

Notice that, if x is very close from 3, then y is very close from 0. Then, we can use the Taylor expansion of the logarithm. Hence,  

\ln(x) = \ln 3 + \ln(1+y) = \ln 3 + \sum_{n=1}^{\infty} (-1)^{n+1} \frac{y^n}{n}.

Now, substitute \frac{x-3}{3}=y in the previous equality. Thus,

\ln(x) = \ln 3 + \sum_{n=1}^{\infty} (-1)^{n+1} \frac{(x-3)^n}{3^n n}.

<em>Radius of convergence.</em>

We find the radius of convergence with the Cauchy-Hadamard formula:

R^{-1} = \lim_{n\rightarrow\infty} \sqrt[n]{|a_n|},

Where a_n stands for the coefficients of the Taylor series and R for the radius of convergence.

In this case the coefficients of the Taylor series are

a_n = \frac{(-1)^{n+1}}{ n3^n}

and in consequence |a_n| = \frac{1}{3^nn}. Then,

\sqrt[n]{|a_n|} = \sqrt[n]{\frac{1}{3^nn}}

Applying the properties of roots

\sqrt[n]{|a_n|} = \frac{1}{3\sqrt[n]{n}}.

Hence,

R^{-1} = \lim_{n\rightarrow\infty} \frac{1}{3\sqrt[n]{n}} =\frac{1}{3}

Recall that

\lim_{n\rightarrow\infty} \sqrt[n]{n}=1.

So, as R^{-1}=\frac{1}{3} we get that R=3.

8 0
3 years ago
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