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Igoryamba
3 years ago
8

Solve X2+4x_12=0 Solve X2+3x_7=0

Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
5 0

Answer:

it's 0

Step-by-step explanation:

probably..............

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I WILL GIVE BRAINLIEST AND THANKS SOLVE THE QUADRATIC EQUATION
laiz [17]

Answer:

x = -0.907, 2.57

Step-by-step explanation:

Quadratic Formula: x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}

Since we are given <em>a</em> = 3, <em>b</em> = -5, and <em>c</em> = -7 from our quadratic, we simply use the Quadratic Formula:

Step 1: Plug in variables

x=\frac{-(-5)+/-\sqrt{(-5)^2-4(3)(-7)} }{2(3)}

Step 2: Solve

x=\frac{5+/-\sqrt{25+ 84} }{6}

x=\frac{5+/-\sqrt{109} }{6}

Step 3: Evaluate for decimals

You should get x = -0.906718 and 2.57338 as your answers.

3 0
3 years ago
Read 2 more answers
I need the answer pls
erastova [34]

The median is B. 2.5

Step-By-Step Explanation:

The dot plot goes by the data

1 2 2 3 3 4

those are six numbers in total!

Since 6 is an even number we'd need to find out the number in between the two numbers in the middle.

In this case that would be 2 and 3.

The number in the middle of 2 and 3 is 2.5

- - - - -

IN CONCLUSION

Your answer is B. 2.5

- - - - -

I hope I helped! :)

5 0
3 years ago
For every 3 hours of babysitting, Kelly makes $36 how much money will she earn if she babysits for seven hours?
svp [43]
You divide 36 by 3 then multiply by 7 you're answer is 12 X 7=
8 0
3 years ago
Read 2 more answers
What is the lcm and hcf of 1/3 and 2/9
Blababa [14]

Step-by-step explanation:

1/1 , 3

3/1 , 3

1 , 1

HCF is 1

LCM is 3 × 1 =3

2/2 , 9

3/1 , 9

3/1 , 3

1 , 1

HCF is 1

LCM is 3 × 3 × 2= 18

6 0
3 years ago
Solve for x in the equation 2 x squared + 3 x minus 7 = x squared + 5 x + 39.
Nastasia [14]

Answer:

\implies x=1\pm \sqrt{47}

Step-by-step explanation:

We want to solve for x in 2x^2+3x-7=x^2+5x+39

You need to group and combine like terms and write in standard form:

2x^2-x^2+3x-5x-7-39=0

\imples x^2-2x-46=0

By comparing to ax^2+bx+c=0, we a=1,b=-2 and c=-46

The solution can be obtained using the quadratic formula.

x=\frac{-b\pm \sqrt{b^2-4ac} }{2a}

We substitute the coefficients to get:

x=\frac{--2\pm \sqrt{(-2)^2-4*1*-46} }{2*1}

x=\frac{2\pm \sqrt{4+4*46} }{2}

x=\frac{2\pm \sqrt{4*47} }{2}

x=\frac{2\pm2\sqrt{47} }{2}

\implies x=1\pm \sqrt{47}

The last choice is correct

5 0
3 years ago
Read 2 more answers
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