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Bond [772]
3 years ago
10

The sum of twice a number and three?​

Mathematics
2 answers:
TiliK225 [7]3 years ago
6 0

Answer:

2x + 3. hope this helps

Step-by-step explanation:

- Zombie

Maslowich3 years ago
3 0

pls mark me as brainliest

<h2>hope it helps</h2>

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A line's y -intercept is 10,and its slope is 9 . What is its equation in slope-intercept form?
LenaWriter [7]

Answer:

y = 9x + 10

Step-by-step explanation:

y = mx + b

Here, m is slope and b is y-intercept

y = 9x + 10

3 0
3 years ago
Can someone please help me with # 2 #13 thanks show work how it's done, please
zavuch27 [327]

Problem 13

10p+10q factors to 10(p+q). If we apply the distributive property, we can distribute the 10 to each term inside (p and q) to get

10(p+q) = (10 times p)+(10 times q) = 10*p + 10*q = 10p+10q

so we get the original expression again. Here 10 is the GCF of the two terms.

--------------------------------------------------------------

Plug p = 1 and q = 2 into the factored form

10*(p+q) = 10*(1+2) = 10*(3) = 30

As a check, let's plug those p,q values into the original expression

10*p+10*q = 10*1+10*2 = 10+20 = 30

We get the same output of 30

6 0
4 years ago
Write an expression that can be used to check the quotient of 646 ÷ 3
Ipatiy [6.2K]
646/3=x
To check it: x*3 should =646
5 0
3 years ago
Read 2 more answers
After eating a meal at a restaurant, we decided to tip 25%, building a grand total of $87.50. What was the price before the tip?
CaHeK987 [17]

Answer:

65.62

Step-by-step explanation:

Given:

After eating a meal at a restaurant, we decided to tip 25%, building a grand total of $87.50.

To find:

Price before tip

Solution:

87.50 × 25% = 21.875

~Round~: 21.875 to 21.88

87.50 - 21 .88 = 65.62

Thus the price before the tip is 65.62

Check Answer:

<em>Formula: Higher number - Lower number ÷ original number × 100</em>

<em>Solve: </em>

<em>87.50 - 65.62 = 21.88</em>

<em>21.88 ÷ 87.50=0.25005714285</em>

<em>0.25005714285 × 100 = 25.0057142857</em>

<em>Round - 25%</em>

 

<u><em>~lenvy~</em></u>

3 0
2 years ago
Given f'(x)=(x-4)(6-2x) find the x-coordinate for the relative minimum of the graph f(x).
vlabodo [156]
<span>The graph you plotted is the graph of f ' (x) and NOT f(x) itself. </span>

Draw a number line. On the number line plot x = 3 and x = 4. These values make f ' (x) equal to zero. Pick a value to the left of x = 3, say x = 0. Plug in x = 0 into the derivative function to get

f ' (x) = (x-4)(6-2x)
f ' (0) = (0-4)(6-2*0)
f ' (0) = -24

So the function is decreasing on the interval to the left of x = 3. Now plug in a value between 3 and 4, say x = 3.5

<span>f ' (x) = (x-4)(6-2x)
</span><span>f ' (3.5) = (3.5-4)(6-2*3.5)
</span>f ' (3.5) = 0.5

The function is increasing on the interval 3 < x < 4. The junction where it changes from decreasing to increasing is at x = 3. This is where the min happens.

So the final answer is C) 3
5 0
3 years ago
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