T = 5, so after 5 years
p(t) = t^3 - 14t^2 + 20t + 120
Take derivative to find minimum:
p’(t) = 3t^2 - 28t + 10
Factor to solve for t:
p’(t) = (3t - 2)(t - 5)
0 = (3t - 2)(t - 5)
0 = 3t - 2
2 = 3t
2/3 = t
Plug 2/3 into original equation, this is a maximum. We want the minimum:
0 = t - 5
5 = t
Plug back into original:
5^3 - 14(5)^2 + 20(5) + 120
125 - 14(25) + 100 + 120
125 - 350 + 220
- 225 + 220
p(5) = -5
Answer: The correct option is (A)
Option (A) is correct.
2x^3+x^2-15x factored completely would be: <em>x(x+3)(2x-5).</em> Not sure which answer choice but I hope that I was some help.
1.
18 units
10 units right and 8 units up.
2.
7 units
3 units right and 4 units down.
3.
8 units
1 units right and 7 units down
4.
8 units
5 units and 3 units down
Answeri really cant see the bottom answers can you take a new picutre
Step-by-step explanation:
