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Licemer1 [7]
3 years ago
13

If m(x) = 2x - 5 and n(x) = 2x + 5, what is n(m(3))?

Mathematics
1 answer:
Rus_ich [418]3 years ago
3 0

9514 1404 393

Answer:

  n(m(3)) = 7

Step-by-step explanation:

n(m(3)) = n(2·3 -5) = n(1) = 2·1 +5

n(m(3)) = 7

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Find the measure of the arc or angle indicated. or find the value of x
bonufazy [111]
#8 you do 360= 112+136+x... then you solve for x. X=112. Now you divide this by two since it is an inscribed angle. For #9 I have this very simplified work in the picture. Sorry I did not do #10

5 0
3 years ago
If 20% of a number is 8, find 10% of that number.
Gemiola [76]

Answer:

20%=8

10%=?

by cross multiplications,

10×8=80

80÷20=4

Hence the answer is 4.

3 0
2 years ago
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Help plz!!!!!<br> Plzzz????
mariarad [96]

Answer:

0Step-by-step explanation888    :8

3 0
3 years ago
13.......................
Alla [95]

Answer:

The answer is (d) ⇒ pq^{2}r\sqrt[3]{pr^{2}}

Step-by-step explanation:

* To simplify the cube roots:

 If its number then the number must be written in the form x³

 then we divide the power by 3 to cancel the radical

 If its variable we divide its power by 3 to cancel the radical

∵ \sqrt[3]{p^{4}q^{6}r^{5}}=p^{\frac{4}{3}}q^{\frac{6}{3}}r^{\frac{5}{3}}}

∴ p^{\frac{4}{3}}q^{2}}r^{\frac{5}{3}}=p^{1\frac{1}{3}}q^{2}r^{1\frac{2}{3}}

∵ p^{\frac{1}{3}}=\sqrt[3]{p}

∵ r^{\frac{2}{3}}=\sqrt[3]{r^{2}}

∴ p(p)^{\frac{1}{3}}q^{2}r(r)^{\frac{2}{3}}=p(\sqrt[3]{p})q^{2}r(\sqrt[3]{r^{2}})

∴ prq^{2}\sqrt[3]{pr^{2}}}

∴ The answer is (d)

5 0
3 years ago
Suppose the heights of 18-year-old men are approximately normally distributed, with mean 65 inches and standard deviation 4 inch
Serhud [2]

Answer:

Step-by-step explanation:

<u>a)</u>

  • Given that ; X ~ N ( µ = 65 , σ = 4 )
  • P ( 64 < X < 66 )

From application of normal distribution ;

  • Z = ( X - µ ) / σ, Z = ( 64 - 65 ) / 4,  Z = -0.25
  • Z = ( 66 - 65 ) / 4,  Z = 0.25

Hence, P ( -0.25 < Z < 0.25 ) = P ( 64 < X < 66 ) = P ( Z < 0.25 ) - P ( Z < -0.25 ) P ( 64 < X < 66 ) = 0.5987 - 0.4013

  • P ( 64 < X < 66 ) = 0.1974

b) X ~ N ( µ = 65 , σ = 4 )

  • P ( 64 < X < 66 )

From normal distribution application ;

  • Z = ( X - µ ) / ( σ / √(n)), plugging in the values,
  • Z = ( 64 - 65 ) / ( 4 / √(12)) = Z = -0.866
  • Z = ( 66 - 65 ) / ( 4 / √(12)) = Z = 0.866

P ( -0.87 < Z < 0.87 )

  • P ( 64 < X < 66 ) = P ( Z < 0.87 ) - P ( Z < -0.87 )
  • P ( 64 < X < 66 ) = 0.8068 - 0.1932
  • P ( 64 < X < 66 ) = 0.6135

c) From the values gotten for (a) and (b), it is indicative that the probability in part (b) is much higher because the standard deviation is smaller for the x distribution.

4 0
3 years ago
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