Add 10 to both sides so that the equation becomes 5x^2 + 11x - 2 = 0.
To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 + bx + c = 0
x = [ -b ± √(b^2 - 4ac) ] / (2a)
x = [ -11 ± √(11^2 - 4(5)(-2)) ] / ( 2(5) )
x = [ -11 ± √(121 - (-40) ) ] / ( 10 )
x = [ -11 ± √(161) ] / ( 10)
x = [ -11 ± sqrt(161) ] / ( 10 )
x = -11/10 ± sqrt(161)/10
The answers are -11/10 + sqrt(161)/10 and -11/10 - sqrt(161)/10.
Answer:
ages would no longer get larger as the mouse hovers over them. The transition would happen over 10s, since this is the default duration.
Step-by-step explanation:
Answer:
1 and 4 are correct. 2 and 3 are not.
Step-by-step explanation:
1.
When x = 0 where does the horse start?
y = 1.5*sin(0 + 0.5)*2*pi + 1.5
y = 1.5*sin(0.5*2pi) + 1.5
y = 1.5*sin(pi) + 1.5 But sin pi = 0
y = 0 + 1.5 So the horse is starting at the midpoint of it's travel.
2.
This one is a trick question. You can reason it without exact answers. At some point the sin(x + 0.5)*2pi will equal 1. When it does 1.5 * 1 + 1.5 = 3.0 At some other point sin(x + 0.5)*2pi = -1. When that happens the whole thing goes to 0. So the total of the distance traveled is 6 not three.
3.
You can figure this one out by letting x = 0.01 When it does then the value of the function is
y = 1.5*sin [(0.01 + 0.5)*2pi] + 1.5
y = 1.5*sin(0.51*2*pi) + 1.5
y = 1.5*sin(3.204424) + 1.5
y = 1.5*(- .0623) + 1.5
y = -0.9418 + 1.5
y = 1.4058 so it is going downward The value is getting smaller.
4.
The horse starts out in the middle of the pole. What does x need to equal so that x + 0.5 = 1 ? And why 1. The answer to why 1 is that then the sine function will equal sin(2*pi)
That happens when x = 0.5 which is 1/2 a minute. If it takes 1/2 a minute to execute 1 complete cycle, then in 5 minutes the cycle will be executed 10 times. This one is correct.
Answer:
hi just need points
Step-by-step explanation:
