Question

Which shows the following expression after the negative exponents have been eliminated? xy^-6/x^-4 y^2, x=/0 y=/0

Answer 1

It would be B, xx4  y2y6

Answer 2

The expression would be $\frac{x^5}{y^8}$ after the negative exponents have been removed.

A negative exponent basically tells us to "flip" the side of the fraction it's on.  This means that y⁻⁶ on the numerator would go to the denominator, and that x⁻⁴ on the denominator would go to the numerator.  This gives us:

$\frac{x\times x^4}{y^2\times y^6}=\frac{x^5}{y^8}$