Question

Can anyone help me with this, please?

Answer 1

$\sqrt[3]{27x^3y^2z}=3x \sqrt[3]{y^2z}$

Step-by-step explanation:

Given that,

An expression, $\sqrt[3]{27x^3y^2z}$

To find,

The value of the given expression.

Solution,

We have,

$\sqrt[3]{27x^3y^2z}$

The rules of exponent are :

$\sqrt[n]{a^m} =a^{m/n}$

and

$(a^b)^c=a^{bc}$

So,

$\sqrt[3]{27x^3y^2z}=\sqrt[3]{27} {\cdot} \sqrt[3]{x^3} {\cdot} \sqrt[3]{y^2z} \\\\=3{\cdot}x{\cdot} \sqrt[3]{y^2z}\\\\=3x \sqrt[3]{y^2z}$

So, the simplified value of the given expression is $3x \sqrt[3]{y^2z}$.

Reference,

brainly.com/question/19627260

Answer 2

9514 1404 393

Answer:

  C.  3x∛(y²z)

Step-by-step explanation:

The relevant rules of exponents are ...

  $\sqrt[n]{a^m} = a^\frac{m}{n}\\\\(a^b)^c=a^{bc}$

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Your expression can be rewritten and simplified as follows.

  $\displaystyle\sqrt[3]{27x^3y^2z}=(3^3x^3y^2z)^\frac{1}{3}=3xy^\frac{2}{3}z^\frac{1}{3}=3x(y^2z)^\frac{1}{3}=\boxed{3x\sqrt[3]{y^2z}}$