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STatiana [176]
3 years ago
10

A baseball is thrown into the air from the top of a 224-foot tall building. The baseball's approximate height over time can be r

epresented by the quadratic equation h(t) = -16t2 + 80t + 224, where t represents the time in seconds that the baseball has been in the air and h(t) represents the baseball's height in feet. When factored, this equation is h(t) = -16(t - 7)(t + 2).
What is a reasonable time for it to take the baseball to land on the ground?

-2 seconds

-9 seconds

-5 seconds

-7 seconds
Mathematics
2 answers:
lianna [129]3 years ago
8 0
H(t) = 0 for t = 7 and for t = -2.

It is reasonable for the time to be positive, 7 seconds.

(The offered answers all appear to be negative, so none are reasonable.)
zimovet [89]3 years ago
4 0

Answer:

7 seconds

Step-by-step explanation:

Given :

A baseball is thrown into the air from the top of a 224-foot tall building.

The baseball's approximate height over time can be represented by the quadratic equation h(t) = -16t^2 + 80t + 224

To Find:  What is a reasonable time for it to take the baseball to land on the ground?

Solution:

Equation : h(t) = -16t^2 + 80t + 224

When factored this equation : h(t) = -16(t - 7)(t + 2)  --A

Now we are supposed to find  reasonable time for it to take the baseball to land on the ground i.e. h =0

So, substitute h = 0 in A

0= -16(t - 7)(t + 2)

t=7,-2

Since time cannot be negative

So, neglect -2

Thus it will taker 7 seconds for baseball to reach the ground.

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Answer:

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Step-by-step explanation:

2x-x=5-3+1

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I think that's it

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Step-by-step explanation:

A: (0,0), B: (3, -4)

To find the distance, use the distance formula. Square-root((0-3)^2+(0-(-4))^2) ---> Square-root((-3)^2 + 4^2) ---> Square-root(9+16) ---> Square-root(25) ---> 5units.

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xz_007 [3.2K]

Answer:

Step-by-step explanation:

-2x + 3y – 4z = 8    ----------------(I)

5x – 3y + 5z = -8    -----------------(II)

7x – 3y + 3z = 8 ------------------(III)

Add equation (I) & (II) and thus y will be eliminated

(I)        -2x + 3y – 4z = 8

(II)        <u>5x – 3y + 5z = -8</u>    {Add}

           3x          + z  = 0   ------------------------(A)

Multiply equation (II) by (-1) and then add with equation (III). Thus y will be eliminated.

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(B)                 <u>2x - 2z  = 16</u>   {Add}

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Plug in x = 2 and z  = - 6 in equation (I)

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               3y = 8 - 20

               3y = -12

                 y = -12/3

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