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AlladinOne [14]

2 years ago

13

One of the legs of a right triangle measures 4cm and other lag measures 3cm. Find the measure of the hypotenuse. If necessary, r

ound to the nearest tenth.

1 answer:

soldier1979 [14.2K]2 years ago

4 0

Answer:

i am trying to answer fast as i can, so sorry for the bad handwriting

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What information do you need to find the area of a triangle using trigonometry?

SCORPION-xisa [38]

Formula of the area of triangle
A=(1/2)a*b*sin(C)
a, b - sides
C- an angle between sides a and b.
Probably, this question means that you need to know sin of the angle.

8 0

3 years ago

A store sells 3 categories of kitchen items: cups, bowls, and spoons. There are 5 types of cups, 4 types of bowls, and 2 types o

Slav-nsk [51]

Answer:

40.

Step-by-step explanation:

That is 5 * 4 * 2

= 40 combinations of a set of bowl, cup and spoon.

6 0

3 years ago

The sum of 15 and two times a number is 29. what is the number?

drek231 [11]

15 + 2x = 29

Subtract 15

2x = 14

Divide by 2

x = 7

The number is 7.

8 0

3 years ago

Read 2 more answers

The average systolic blood pressure was found to be 140 mm for people who have high responsibility jobs, specifically investment

9966 [12]

Answer:

Option B)

$H_{0}: \mu = 140\text{ mm}\\H_A: \mu < 140\text{ mm}$

Step-by-step explanation:

We are given the following in the question:

Hypothesis:

The doctors and u=instructor claims that practicing yoga reduces blood pressure and hence is beneficial to people.

Population mean, μ = 140 mm

Sample mean, $\bar{x}$ = 139 mm

Sample size, n = 51

Sample standard deviation, s = 5 mm

Thus, we can design the null hypothesis and alternate hypothesis as

$H_{0}: \mu = 140\text{ mm}\\H_A: \mu < 140\text{ mm}$

The null hypothesis states that the population have a blood pressure of 140 mm. The alternate hypothesis states that yoga reduces the blood pressure and the sample has a blood pressure less than 140 mm.

Thus, the correct answer is

Option B)

$H_{0}: \mu = 140\text{ mm}\\H_A: \mu < 140\text{ mm}$

3 0

2 years ago

someone please explain to me how to find the area PLEASE! Find the area and perimeter of quadrilateral ABCD below. Explain your

Lunna [17]

Answer:

Part A) The area of the figure is $24\ units^{2}$

Part B) The perimeter of the figure is $20\ units$

Step-by-step explanation:

step 1

Find the area of the figure

we know that

The area of the figure is equal to the area of triangle ABD plus the area of triangle BCD

The area of triangle is equal to

$A=\frac{1}{2}bh$

<u>Area of triangle ABD</u>

Observing the graph

$b=BD=(-2+8)=6\ units$

$h=(9-5)=4\ units$

substitute

$A=\frac{1}{2}(6)(4)=12\ units^{2}$

<u>Area of triangle BCD</u>

Observing the graph

$b=BD=(-2+8)=6\ units$

$h=(5-1)=4\ units$

substitute

$A=\frac{1}{2}(6)(4)=12\ units^{2}$

The area of the figure is

$12\ units^{2}+12\ units^{2}=24\ units^{2}$

step 2

Find the perimeter of the figure

we know that

The perimeter of the figure is equal to

$P=AB+BC+CD+AD$

we have

$A(-5,1),B(-8,5),C(-5,9),D(-2,5)$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

$d=\sqrt{(5-1)^{2}+(-8+5)^{2}}=5\ units$

Find the distance BC

$d=\sqrt{(9-5)^{2}+(-5+8)^{2}}=5\ units$

Find the distance CD

$d=\sqrt{(5-9)^{2}+(-2+5)^{2}}=5\ units$

Find the distance AD

$d=\sqrt{(5-1)^{2}+(-2+5)^{2}}=5\ units$

substitute the values

$P=5+5+5+5=20\ units$

7 0

3 years ago