The quantitative relation between two amounts showing the number of times one value contains or it’s contained within the other.
FOR THE FIRST PROBLEM:
Differentiating p^2 + 2q^2 = 1100 with respect to time => 2p(dp/dt) + 4q(dq/dt) = 0
<span>dp/dt = -2q/p(dq/dt) </span>
<span>R = pq </span>
<span>dR/dt = p(dq/dt) + q(dp/dt) = -p²/2q(dp/dt) + q(dp/dt) = (2q² - 1100)/2q * (dp/dt) + q(dp/dt) </span>
<span>A = (2q - 550/q)
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Answer:
a. 55 hours
b. 1.9 degrees C
Step-by-step explanation:
This means for each hour the temperature drops 0.08. This is the expression 0.08x where x is number of hours.
a.) If the temperature has dropped 4.4, then 4.4 = 0.08x. Solving for x will give the number of hours it takes to drop 4.4.
4.4 = 0.08x
4.4 / 0.08 = x
55 = x
b.) If the temperature after 55 hours and dropping 4.4 is -2.5, then the temperature at the start would be -2.5 + 4.4 = 1.9. The temperature at noon was 1.9 degrees celsius.
Alright. It seems like the triangle that has the 45 degree angle with angles c & d is an isosceles triangle which meas two sides are equal.
If that is true, angle d would be 45. Add 45 and 45 together to get 90, which is angle c. The angle right across from c, a, will be 90 as well. Add 90 and 45 to get 135 and then do 180 - 135 to get angle b. Angle b should equal 45 as well. So adding each of the angles together, 90 + 45 + 90 + 45 = 360
Your final answer is 360.