Ok! So, given a quadratic function<span>, </span>y<span> = ax</span>2<span> + bx + c, when "a" is positive, the </span>parabola <span>opens upward and the vertex is the minimum value. On the other hand, if "a" is negative, the graph opens downward and the vertex is the maximum value. Now, let's refer back to our original graph, </span>y<span> = </span><span>x2</span><span>, where "a" is 1.
Hope this helps.</span>
Answer:
56
Step-by-step explanation:
10y+6
10(5)+6
10*5=50
50+6=56
The answer is B your welcome
Answer:
Step-by-step explanation:
This is your correct answer if ur aim is simplification!