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stiks02 [169]
3 years ago
8

Naseer has inserted an image into his document but needs the image to appear on its own line.

Computers and Technology
1 answer:
defon3 years ago
8 0
In front of text yuhhhhhh :D
You might be interested in
How many bits does it take to store a 3-minute song using an audio encoding method that samples at the rate of 40,000 bits/secon
blondinia [14]

Answer:

115200000 bits

Explanation:

Given Data:

Total Time = 3 minute = 3 x 60 sec = 180 sec

Sampling rate = 40,000 bits / sample

Each sample contain bits = 16 bits /sample

Total bits of song = ?

Solution

Total bits of song = Total Time x Sampling rate x Each sample contain bits

                             = 180 sec x 40,000 bits / sec x 16 bits /sample

                             = 115200000 bits

                             =  115200000/8 bits

                             = 14400000 bytes

                             = 144 MB

There are total samples in one second are 40000. Total time of the song is 180 seconds and one sample contains 16 bits. so the total bits in the song are 144 MB.

5 0
3 years ago
For each of the following memory accesses indicate if it will be a cache hit or miss when carried out in sequence as listed. Als
nika2105 [10]

Answer:

Explanation:

Operation Address Hit? Read Value

Read 0x834 No Unknown

Write 0x836 Yes (not applicable)

Read 0xFFD Yes CO

6 0
3 years ago
Which examples are credible sources that could be used for an essay on the environment? Pick all that apply.
ahrayia [7]

Answer:

article, website run by non profit, website for fed agency

8 0
3 years ago
What is the depth of the following tree?
disa [49]

Answer:

The correct answer to this question is given below in the explanation section.

Explanation:

This given tree has four nodes. Node A is a parent node in this tree, while B, C, and D are child nodes of A.

The given options about the depth of the tree are:

  • A). 0
  • B). 1
  • C). 2
  • D). 3

The correct option to this question is (B) i.e. the depth of this tree is 1.

Because we know that the depth of a node M in the tree is the length of the path from the root of the tree to M. So, in this case,  the depth of node A to node B, C, and D  is 1. So, the correct option to this question is B. i.e the depth of the given tree is 1.

6 0
2 years ago
Write a program that will ask for the user to input a filename of a text file that contains an unknown number of integers. And a
Ratling [72]

Answer: Provided in the explanation section

Explanation:

Code provided below in a well arranged format

inputNos.txt

70

95

62

88

90

85

75

79

50

80

82

88

81

93

75

78

62

55

89

94

73

82

___________________

StandardDev.java

import java.io.File;

import java.io.FileNotFoundException;

import java.util.Scanner;

public class StandardDev {

public static void main(String[] args) {

//Declaring variables

String filename;

int count = 0, i = 0;

Scanner sc1 = null;

int min, max;

double mean, stdDev;

int nos[] = null;

/*

* Creating an Scanner class object which is used to get the inputs

* entered by the user

*/

Scanner sc = new Scanner(System.in);

//Getting the input entered by the user

System.out.print("Enter the name of the filename :");

filename = sc.next();

try {

//Opening the file

sc1 = new Scanner(new File(filename));

//counting no of numbers in the file

while (sc1.hasNext()) {

sc1.nextInt();

count++;

}

sc1.close();

sc1 = new Scanner(new File(filename));

//Creating an Integer based on the Count

nos = new int[count];

//Populating the values into an array

while (sc1.hasNext()) {

nos[i] = sc1.nextInt();

i++;

}

sc1.close();

//calling the methods

min = findMinimum(nos);

max = findMaximum(nos);

mean = calMean(nos);

stdDev = calStandardDev(nos, mean);

//Displaying the output

System.out.println("Read from file :" + count + " values");

System.out.println("The Minimum Number is :" + min);

System.out.println("The Maximum Number is :" + max);

System.out.printf("The Mean is :%.2f\n", mean);

System.out.printf("The Standard Deviation is :%.2f\n", stdDev);

} catch (FileNotFoundException e) {

e.printStackTrace();

}

}

//This method will calculate the standard deviation

private static double calStandardDev(int[] nos, double mean) {

//Declaring local variables

double standard_deviation = 0.0, variance = 0.0, sum_of_squares = 0.0;

/* This loop Calculating the sum of

* square of eeach element in the array

*/

for (int i = 0; i < nos.length; i++) {

/* Calculating the sum of square of

* each element in the array    

*/

sum_of_squares += Math.pow((nos[i] - mean), 2);

}

//calculating the variance of an array

variance = ((double) sum_of_squares / (nos.length - 1));

//calculating the standard deviation of an array

standard_deviation = Math.sqrt(variance);

return standard_deviation;

}

//This method will calculate the mean

private static double calMean(int[] nos) {

double mean = 0.0, tot = 0.0;

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Calculating the sum of all the elements in the array

tot += nos[i];

}

mean = tot / nos.length;

return mean;

}

//This method will find the Minimum element in the array

private static int findMinimum(int[] nos) {

int min = nos[0];

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Finding minimum element

if (nos[i] < min)

min = nos[i];

}

return min;

}

//This method will find the Maximum element in the array

private static int findMaximum(int[] nos) {

int max = nos[0];

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Finding minimum element

if (nos[i] > max)

max = nos[i];

}

return max;

}

}

_____________________

Output:

Enter the name of the filename :inputNos.txt

Read from file :22 values

The Minimum Number is :50

The Maximum Number is :95

The Mean is :78.45

The Standard Deviation is :12.45

cheers i hope this helped !!!

7 0
3 years ago
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