A hockey puck has a diameter of 3 inches and rolls on its edge for 24 rotations. How far did it roll before falling flat?
1 answer:
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Answer:
1, -6
Step-by-step explanation:
Since there are alike numbers, add them together.
4x+x= 5x
Now the function is: f(x)= +5x-6
The function is in +bx+c form.
So find the factors of a x c = b.
Factors of -6(a) that fits (b)5 is (-1,6).
Then you just factor it:
f(x)= +5x-6
(x-1)(x+6)
x-1= 0 x+6=0
+1 +1 -6 -6
x=1 x=-6
Those are the real zeroes: 1, -6
Answer:
V=25088π vu
Step-by-step explanation:
Because the curves are a function of "y" it is decided to take the axis of rotation as y
, according to the graph 1 the cutoff points of f(y)₁ and f(y)₂ are ±2
f(y)₁ = 7y²-28; f(y)₂=28-7y²
y=0; x=28-0 ⇒ x=28
x=0; 0 = 7y²-28 ⇒ 7y²=28 ⇒ y²= 28/7 =4 ⇒ y=√4 =±2
Knowing that the volume of a solid of revolution V=πR²h, where R²=(r₁-r₂) and h=dy then:
dV=π(7y²-28-(28-7y²))²dy ⇒dV=π(7y²-28-28+7y²)²dy = 4π(7y²-28)²dy
dV=4π(49y⁴-392y²+784)dy integrating on both sides
∫dV=4π∫(49y⁴-392y²+784)dy ⇒ solving ∫(49y⁴-392y²+784)dy
49∫y⁴dy-392∫y²dy+784∫dy =
V=4π( ) evaluated -2≤y≤2, or 2(0≤y≤2), also
⇒ V=25088π vu
