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zavuch27 [327]
3 years ago
11

A cell phone company charges $400 for a new phone and $50 for a monthly plan. If C (t) is a rational function that represents th

e average monthly cost of owning the cell phone, what is the range of the function?
R: ℝ
R: (–∞, ∞)
R: (0, 400)
R: (50, 450)
Mathematics
1 answer:
guapka [62]3 years ago
7 0

Answer:

its c

Step-by-step explanation:

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Please help I need answers #5 and #6 more, but if you could do all that would be great thanks it’s urgent!!!
Rudiy27

Answer:

Step-by-step explanation:

Answer for #5

Two Points M(-7,1) and N(5,1).

1. Formula is Distance = \sqrt{(x2-x1)^2 - (y2-y1)^2}

2. Let’s say (x1,y1) = (-7,1) and (x2,y2) =(5,1)

3. Distance = \sqrt{(5-(-7))^2 + (1-1)^2} = \sqrt{(5+7)^2-(0)^2} = \sqrt{(12)^2+0} =\sqrt{144} = 12}

so distance between two warehouses is 12 miles

Answer #6

In the question it is saying the “Distance between two stores is half the distance between warehouses“ so it is   \frac{12}{2} = 6 miles

Answer #7

S1(-4,1) and distance of S1 and M is 3 Miles.

Answer #8

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4 0
3 years ago
Hello I need help Finding the probability
Stolb23 [73]
Each petal of the region R is the intersection of two circles, both of diameter 10. Each petal in turn is twice the area of a circular segment bounded by a chord of length 5\sqrt2, which implies the segment is subtended by an angle of \dfrac\pi2. This means the area of the segment is

\text{area}_{\text{segment}}=\text{area}_{\text{sector}}-\text{area}_{\text{triangle}}
\text{area}_{\text{segment}}=\dfrac{25\pi}4-\dfrac{25}2

This means the area of one petal is \dfrac{25\pi}2-25, and the area of R is four times this, or 50\pi-100.

Meanwhile, the area of G is simply the area of the square minus the area of R, or 10^2-(50\pi-100)=200-50\pi.

So

\mathbb P(X=R)=\dfrac{50\pi-100}{100}=\dfrac\pi2-1
\mathbb P(X=G)=\dfrac{200-50\pi}{100}=2-\dfrac\pi2
\mathbb P((X=R)\land(X=G))=0 (provided these regions are indeed disjoint; it's hard to tell from the picture)
\mathbb P((X=R)\lor(X=G))=\mathbb P(X=R)+\mathbb P(X=G)=1

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3 years ago
There were 340,000 cattle placed on bead write an equivalent ratio that could be used to find how many of these cattle were betw
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170,000 FEED POUNDS....
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3 years ago
Help me!!!!!!!!!!!! And look at the picture plzzzz!!!!
liubo4ka [24]

Answer: 72

Step-by-step explanation:

Set it up as a ratio

\frac{12}{15} =\frac{x}{90} \\15x=1080\\x=72

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2 years ago
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