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Pavel [41]
2 years ago
8

A recipe for waffles calls for 1 1/4 cups of water. If you only had a 1/2 cup measure, how many times would you have to fill it

to add all of the water to the batter?
A. 2 1/4 times
B. 2 times
C. 2 1/2 times
D. 2 3/4 times
Mathematics
1 answer:
nikitadnepr [17]2 years ago
6 0

Answer:

D

Step-by-step explanation:

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14(8-W)=0
(14*8)-(14*W)=0
112-14W=0
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W=8
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Im really bad at the functions stuff so- yk help
atroni [7]

Answer:Isolate the variable by dividing each side by factors that don't contain the variable.

w =-3u/2+2

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2 years ago
Find the equation of the line through point (2,2) and parallel to y=x+4. Use a forward slash (i.e.”/“) for fractions (e.g. 1/2 f
aleksandr82 [10.1K]

Answer:

The equation of the line is, y = x

Step-by-step explanation:

The constraints of the required linear equation are;

The point through which the line passes = (2, 2)

The line to which the required line is parallel = y = x + 4

Two lines are parallel if they have the same slope, therefore, we have;

The slope of the line, y = x + 4 is m = 1

Therefore, the slope of the required line = 1

The equation of the required lime in point and slope form becomes;

y - 2 = 1 × (x - 2)

∴ y = x - 2 + 2 = x

The equation of the required line is therefore, y = x

5 0
3 years ago
(1) Sixty million seventy-two is written
katovenus [111]
Standard form


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5 0
3 years ago
Read 2 more answers
En la división sintética sólo son tomados en cuenta los coeficientes del divisor?
Airida [17]

La división sintetica sirve para el cociente entre polinomios, la cual es particularmente util para cuando tenemos un numerador de grado alto y un denominador de grado 1.

Veremos que si, en la división sintética solo son tomados en cuenta los coeficientes del divisor.

Para explicarla, usaremos un ejemplo.

x^3 - 2x^2 + 5x + 3  será el <u>numerador</u>

x - 2 será el <u>denominador.</u>

Para poder aplicar la división sintetica, el maximo exponente en el <u>denominador </u>debe ser uno.

Así, nuestro cociente es:

\frac{x^3 - 2x^2 + 5x + 3}{x-2}

Procedemos a igualar el <u>denominador</u> a cero:

x - 2 = 0

x = 2

Ahora veremos los coeficientes del <u>numerador</u> (el <u>numerador </u>es el <u>divisor</u>).

Lo que debemos hacer es tomar cada coeficiente (comenzando por los que multiplican a los terminos con mayor exponente) y multiplicarlos por este número.

En este caso, el primer coeficiente es 1.

2*1 = 2

Ahora le sumamos esto al proximo coeficiente, que es -2:

-2 + 2 = 0

Multiplicamos esto por el valor de x, que es 2.

2*0 = 0

Ahora sumamos esto al proximo coeficiente, que es 5

5 + 0  = 5

Multiplicamos esto por el valor de x, que es 2:

5*2 = 10

Sumamos esto al ultimo coeficiente, que es 3.

10 + 3 = 13

Este ultimo valor es el residuo, y los primeros 3 números que obtuvimos son los coeficientes del cociente, entonces el cociente será:

1*x^2 + 0*x + 10 = x^2 + 10

Como vimos, solo usamos los coeficientes del numerador/divisor para realizar esta operación, por lo que si, solo los coeficientes del divisor son tomados en cuenta.

Si quieres aprender más, puedes leer:

brainly.com/question/10466403

3 0
2 years ago
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