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katrin2010 [14]
3 years ago
9

Need help on the three table please help

Mathematics
2 answers:
Dimas [21]3 years ago
8 0

Answer:

Step-by-step explanation:

hard work lol

Evgesh-ka [11]3 years ago
5 0
What grade are you in
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What's 24 - 5.9 and how do you show your work
ziro4ka [17]

Answer:

18.1

Step-by-step explanation:

24-5.9=18.1

8 0
3 years ago
What is 21/75 in simplest form
Tomtit [17]
7/25 Is 21/75 in simplest form since 7 is a prime number it can't go any further.
8 0
4 years ago
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!!!PLEASE HELP!!!<br> explain the error
Alchen [17]

Answer:

Step-by-step explanation:

x is greater than minus 3. You have everything right but the graph. The arrowhead goes the other way. Around -3 is as small as x gets.

0====0====0====0====0

-3       -2      -1        O       1

O------------------------------->

5 0
3 years ago
Find the volume of the oblique rectangular prism with length 8cm, width 7cm, and height 9cm.
denis-greek [22]

Answer:

<h2>V = 504 cm³</h2>

Step-by-step explanation:

The formula of an area of a rectangular prism <em>l × w × h:</em>

V=lwh

<em>l</em><em> - length</em>

<em>w</em><em> - width</em>

<em>h</em><em> - height</em>

<em />

We have <em>l = 8cm, w = 7cm, h = 9cm</em>.

Substitute:

V=(8)(7)(9)=504\ cm^3

4 0
3 years ago
A social psychologist wants to know whether students' performance on a problem solving task is lowered by having other people lo
Orlov [11]

Answer:

Yes, there is sufficient evidence to conclude that performance on the problem solving task is lowered by having onlookers.

Step-by-step explanation:

Null hypothesis: The performance on the problem solving task is lowered by having onlookers.

Alternate hypothesis: The performance on the problem solving task is not lowered by having onlookers.

Test statistic (t) = (sample mean - population mean) ÷ (sample sd/√n)

sample mean = 89.8

population mean = 89.1

sample sd = √sample variance = √84.6 = 9.198

n = 21

Degree of freedom = n-1 = 21-1 = 20

Assuming a 5% significance level

The test is a two-tailed test. Critical values corresponding to 20 degrees of freedom and 5% significance level are -2.086 and 2.086

Test statistic (t) = (89.8 - 89.1) ÷ (9.198/√21) = 0.7 ÷ 2.007 = 0.349

Conclusion:

Fail to reject the null hypothesis because the test statistic 0.349 falls within the region bounded by the critical values.

There is sufficient evidence to conclude that performance on the problem solving task is lowered by having onlookers.

4 0
3 years ago
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