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nadezda [96]
3 years ago
6

Which answer gives statements that should be used to prove angles 2 and 7 are supplementary angles?

Mathematics
1 answer:
Neko [114]3 years ago
6 0

Answer:

Angles 2 and 6 are congruent as corresponding angles

Angles 6 and 7 form a linear pair.

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SOMEONE PLEASE HELP! THANK YOU
Andrew [12]

Answer:

arithmetic; common difference; 8

Step-by-step explanation:

Let's first define arithmetic and geometric sequences:

<u>Arithmetic</u>:

Arithmetic sequences are made up of successive terms that share a common difference. In other words, if the sequence is, say: a, b, c, d, then we know that: d - c = c - b = b - a

<u>Geometric</u>:

Geometric sequences are made up of successive terms that share a common ratio. In other words, if the sequence is, say: e, f, g, h, then we know that:

h/g = g/f = f/e   (where the / denotes division)

Here, let's try applying the arithmetic sequence rule to the three terms:

2, 10, 18

18 - 10 = 8

10 - 2 = 8

Ah, we see that the common difference is indeed 8, so this is an arithmetic sequence.

Thus, the answer is: arithmetic; common difference; 8.

<em>~ an aesthetics lover</em>

5 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP!
vazorg [7]

Answer:

A. \displaystyle \frac{6}{10}

Step-by-step explanation:

\displaystyle \frac{9}{15} = \frac{6}{10}

Greatest Common Divisor [GCD]: 1½

I am joyous to assist you anytime.

4 0
3 years ago
Pls help:( this is due by the end of the day!! 16 points!
Firlakuza [10]

Answer:

P=90

q=122

Step-by-step explanation:

3 0
3 years ago
How to solve 2x - 3x/2 = -x + 1/3<br> PLZ HELP!
astraxan [27]
I got 2/3 .... Is it correct? Seems weird...
5 0
3 years ago
Read 2 more answers
Question 3 Determine the leg lengths between the two points: (6, -3) and (-2,4).
Shalnov [3]

Answer:

9

Step-by-step explanation:

→You can use the Pythagorean Theorem to solve this, by plugging in the numbers, like so:

\begin{gathered}a^2+b^2=c^2\\x^2+(x-3)^2=(x+3)^2\end{gathered}

a

2

+b

2

=c

2

x

2

+(x−3)

2

=(x+3)

2

x^2+x^2-6x+9=x^2+6x+9x

2

+x

2

−6x+9=x

2

+6x+9

→Subtract x^2-6x+9x

2

−6x+9 from both sides:

x^2 = 12xx

2

=12x

→Subtract 12x from both sides:

x^2 -12x=0x

2

−12x=0

→Factor out x:

x(x-12)=0x(x−12)=0

→Separate, set = to 0, and solve:

\begin{gathered}x = 0\\x -12=0\end{gathered}

x=0

x−12=0

→ Add 12 to both sides: x = 12x=12

→So we have 0 and 12, as our answers. However, we cannot have 0 as a side length, since this would not be possible.

→All we need to do is take 12, and plug it into the equation for the shortest leg.

\begin{gathered}x - 3=?\\12-3=9\end{gathered}

x−3=?

12−3=9

3 0
3 years ago
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