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Harman [31]
3 years ago
12

Please help with some RSM homework:(​

Mathematics
1 answer:
bija089 [108]3 years ago
4 0

Answer:

k<3.5 or k>3.5

Step-by-step explanation:

k²-7k+12.25>0

(k-3.5)²

k²-7k+12.25

k²-2k·3.5+(√12.25)²

(k-3.5)²

k-3.5<0 or k-3.5>0

k-3.5 or k-3.5

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The correct answer is 4> -3
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Fran naders insurance coverage bodily Injury 25/100 and $100,000 property damage. It has a $50-deductible comprehensive and a $5
vladimir2022 [97]

Answer:

$250,000

Step-by-step explanation:

This is the correct question below;

Fran naders insurance coverage bodily Injury 25/100 and $100,000 property damage. It has a $50-deductible comprehensive and a $50-deductible collision. Her car is in age group C and Insurance-rating group 10(or C,10) and her driver-rating Factor is 1.50.

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7 0
3 years ago
Read 2 more answers
Mikey has $100 to spend on books. She wants to buy at least 14 books. Hardback books cost $15.00 and paperback books cost $7.00.
fomenos
A. x+y<100
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3 years ago
Find an asymptote of this conic section. 9x^2-36x-4y^2+24y-36=0
ki77a [65]
We will begin by grouping the x terms together and the y terms together so we can complete the square and see what we're looking at. (9x^2-36x)-(4y^2+24y)-36=0.  Now we need to move that 36 over by adding to isolate the x and y terms.  (9x^2-36x)-(4y^2+24y)=36.  Now we need to complete the square on the x terms and the y terms.  Can't do that, though, til the leading coefficients on the squared terms are 1's.  Right now they are 9 and 4.  Factor them out: 9(x^2-4x)-4(y^2-6y)=36.  Now let's complete the square on the x's. Our linear term is 4.  Half of 4 is 2, and 2 squared is 4, so add it into the parenthesis.  BUT don't forget about the 9 hanging around out front there that refuses to be forgotten.  It is a multiplier.  So we are really adding in is 9*4 which is 36.  Half the linear term on the y's is 3.  3 squared is 9, but again, what we are really adding in is -4*9 which is -36.  Putting that altogether looks like this thus far: 9(x^2-4x+4)-4(y^2-6y+9)=36+36-36.  The right side simplifies of course to just 36.  Since we have a minus sign between those x and y terms, this is a hyperbola.  The hyperbola has to be set to equal 1.  So we divide by 36.  At the same time we will form the perfect square binomials we created for this very purpose on the left: \frac{(x-2)^2}{4}- \frac{(y-3)^2}{9}=1.  Since the 9 is the bigger of the 2 values there, and it is under the y terms, our hyperbola has a horizontal transverse axis.  a^2=4 so a=2; b^2=9 so b=3.  Our asymptotes have the formula for the slope of m=+/- \frac{b}{a} which for us is a slope of negative and positive 3/2.  Using the slope and the fact that we now know the center of the hyperbola to be (2, 3), we can solve for b and rewrite the equations of the asymptotes.  3= \frac{3}{2}(2)+b give us a b of 0 so that equation is y = 3/2x.  For the negative slope, we have 3=- \frac{3}{2}(2)+b which gives us a b value of 6.  That equation then is y = -3/2x + 6.  And there you go!
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3 years ago
I need help asap.!!!!!
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The answer is for 23-24 is 23 d and for 24 it’s g
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