To answer your question, this could be the possible answer and i hope you understand and interpret it correctly:
<span>[Integrate [0, 1/2] xcos(pi*x
let u=x so that du=dx
and v=intgral cos (xpi)dx
v=(1/pi)sin(pi*x)
integration by parts
uv-itgral[0,1/2]vdu just plug ins
(1/pi)sinpi*x]-(1/pi)itgrlsin(pi*x)dx from 0 to 1/2
(1/pi)x sinpi*x - (1/pi)[-(1/pi) cos pi*x] from 0 to 1/2
=(1/2pi)+(1/pi^2)[cos pi*x/2-cos 0]
=1/2pi - 1/2pi^2
=(pi-2)/2pi^2 ans</span>
Answer:
56
Step-by-step explanation:
Please write (x4 – 2) ÷ (x + 1) as <span>(x^4 – 2) ÷ (x + 1).
We can find the remainder using synth. div. as follows:
_________________
-1 / 1 0 0 0 -2
-1 1 -1 1
------------------------------
1 -1 1 -1 -1
The remainder is -1.</span>
Answer:
-2
Step-by-step explanation:
rise over run or, y2-y1/x2-x1
