Answer:
The upper left
Step-by-step explanation:
Огорс
1 answer:
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Answer:
a) The claim is not plausible
b) claim is plausible and the type of bias here is response bias
Step-by-step explanation:
Given data:
Number of political parties = 4
coffee party got the support of 435 out of 1183 randomly selected voters in a poll conducted.
<u>A)</u><u> Construct and interpret a 98% confidence interval to estimate the proportion of voters who support the coffee party </u>
H0 ( null hypothesis ) : p = 0.42
Ha ( alternate hypothesis ) : p ≠ 0.42
z value for 98% confidence interval = 2.326
using 98% confidence interval the value of p = ( 0.3668, 0.3686 )
hence the claim is not plausible
<u>B) Determine the type of bias </u>
Assume the actual number of people = 1200
and 17 people did not respond
hence number of people who responded = 1200 - 17 = 1183
Therefore the claim by the manager is plausible because 17 people did not respond and the type of bias here is response bias
<em>attached below is a detailed solution of the problem of the A part </em>
Answer:
6.56% probability that a real emergency situation exists.
Step-by-step explanation:
We have these following probabilities:
A 0.4% probability that a real emergency situation exists.
A 99.6% probability that a real emergency situation does not exist.
If an emergency situation exists, a 95% probability that the alarm sounds.
If an emergency situation does not exist, a 2% probability that the alarm sounds.
The problem can be formulated as the following question:
What is the probability of B happening, knowing that A has happened.
It can be calculated by the following formula
Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.
In this problem:
What is the probability of a real emergency situation existing, given that the alarm has sounded.
P(B) is the probability of there being a real emergency situation. So .
P(A/B) is the probability of the alarm sounding when there is a real emergency situation. So P(A/B) = 0.95.
P(A) is the probability of the alarm sounding. This is 95% of 0.4%(real emergency situation) and 2% of 99.6%(no real emergency situation). So
P(A) = 0.95*0.04 + 0.02*0.996 = 0.05792
Given that the alarm has just sounded, what is the probability that a real emergency situation exists?
6.56% probability that a real emergency situation exists.