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tatuchka [14]
3 years ago
14

What is the answer to 2/3 - 7/15=

Mathematics
1 answer:
elixir [45]3 years ago
7 0

Answer:

1/5

Step-by-step explanation:

2/3 - 7/15

Now when dealing with fractions, alas make the dominator ( bottom number the same), and the rule of thumb is, whatever u do to the bottom, must be done to the top

2 7

-------- - - - - - -

3 15

So now u should think, how to make 3 to 15, so u multiply it by 5, therefore u would also need to multiply it to the top

2 x 5 7

-------- - - - - - -

3 x 5 15

10 7

-------- - - - - - -

15 15

Now just minus horizontally ( u don't need to minus the dominator)

3

---------

15

Now can u make this fraction smaller? As in, is there a number that u can divide to the top and bottom, yes, that number is 3 in this case

3 ÷3

---------

15 ÷3

= 1

- - - - -

5

Thats your final answer

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What is the product of any integer and -1
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Answer:

The negative counterpart

Step-by-step explanation:

x * -1 = -x

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Hope this helps.

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Help me wit dis plz for for 20 points​
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How to know if a function is periodic without graphing it ?
zhenek [66]
A function f(t) is periodic if there is some constant k such that f(t+k)=f(k) for all t in the domain of f(t). Then k is the "period" of f(t).

Example:

If f(x)=\sin x, then we have \sin(x+2\pi)=\sin x\cos2\pi+\cos x\sin2\pi=\sin x, and so \sin x is periodic with period 2\pi.

It gets a bit more complicated for a function like yours. We're looking for k such that

\pi\sin\left(\dfrac\pi2(t+k)\right)+1.8\cos\left(\dfrac{7\pi}5(t+k)\right)=\pi\sin\dfrac{\pi t}2+1.8\cos\dfrac{7\pi t}5

Expanding on the left, you have

\pi\sin\dfrac{\pi t}2\cos\dfrac{k\pi}2+\pi\cos\dfrac{\pi t}2\sin\dfrac{k\pi}2

and

1.8\cos\dfrac{7\pi t}5\cos\dfrac{7k\pi}5-1.8\sin\dfrac{7\pi t}5\sin\dfrac{7k\pi}5

It follows that the following must be satisfied:

\begin{cases}\cos\dfrac{k\pi}2=1\\\\\sin\dfrac{k\pi}2=0\\\\\cos\dfrac{7k\pi}5=1\\\\\sin\dfrac{7k\pi}5=0\end{cases}

The first two equations are satisfied whenever k\in\{0,\pm4,\pm8,\ldots\}, or more generally, when k=4n and n\in\mathbb Z (i.e. any multiple of 4).

The second two are satisfied whenever k\in\left\{0,\pm\dfrac{10}7,\pm\dfrac{20}7,\ldots\right\}, and more generally when k=\dfrac{10n}7 with n\in\mathbb Z (any multiple of 10/7).

It then follows that all four equations will be satisfied whenever the two sets above intersect. This happens when k is any common multiple of 4 and 10/7. The least positive one would be 20, which means the period for your function is 20.

Let's verify:

\sin\left(\dfrac\pi2(t+20)\right)=\sin\dfrac{\pi t}2\underbrace{\cos10\pi}_1+\cos\dfrac{\pi t}2\underbrace{\sin10\pi}_0=\sin\dfrac{\pi t}2

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More generally, it can be shown that

f(t)=\displaystyle\sum_{i=1}^n(a_i\sin(b_it)+c_i\cos(d_it))

is periodic with period \mbox{lcm}(b_1,\ldots,b_n,d_1,\ldots,d_n).
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3 years ago
Is the expression 4 - x the same as x – 4? Explain
jarptica [38.1K]

Answer:

Yes

Step-by-step explanation:

The order of the factors does not alter the product

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