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den301095 [7]
3 years ago
13

What is 2/5 ÷ 4 2/3​

Mathematics
2 answers:
Vikentia [17]3 years ago
6 0

Answer:

3/35

Step-by-step explanation:

2/5 ÷ 14/3

2/5 × 3/14

= 3/35

kkurt [141]3 years ago
6 0
The answer might be 6/55 because I changed the mixed number into an improper number then I divided them
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How to solve the sum of two numbers is 13. twice the larger increased by three times the smaller is 31. find the numbers?
worty [1.4K]
13 divided by 2 is 6.5 and 31 divide by 2 is 15.5 I hope this helped 
8 0
3 years ago
Help me please anyone I need help asap
Lera25 [3.4K]
156cm=1.56m=0.0156km
5 0
3 years ago
A man is parasailing on a lake. The rope he is holding is 150 feet long and he is 45 feet above the water. What is the horizonta
ss7ja [257]

9514 1404 393

Answer:

  143.1 ft

Step-by-step explanation:

Assuming the rope is tied to the boat, and that the geometry can be modeled by a right triangle, the Pythagorean theorem is helpful.

  150² = 45² + d²

  d = √(150² -45²) = √20475 ≈ 143.1 . . . . feet

The horizontal distance between the man and the boat is about 143.1 feet.

3 0
3 years ago
I NEED IMMEDIATE HELP!!!!
DerKrebs [107]
<h2>Hello!</h2>

The answers are:

C) (3+xz)(-3+xz)

D) (y^2-xy)(y^2+xy)

F) (64y^2+x^2)(-x^2+64y^2)

<h2>Why?</h2>

To know which of the products results in a difference of square, we need to remember the difference of squares from:

The difference of squares form is:

(a+b)(a-b)=a^{2}-b^{2}

So, discarding each of the given options in order to find which products result in a difference of squares, we have:

<h2>A)</h2>

(x-y)(y-x)=xy-x^{2}-y^{2} +yx=-x^{2} -y^{2}

So, the obtained expression is not a difference of squares.

<h2>B)</h2>

(6-y)(6-y)=36-6y-6y+y^{2}=y^{2}-12y+36

So, the obtained expression is not a difference of squares.

<h2>C)</h2>

(3+xz)(-3+xz) =(xz+3)(xz-3)=(xz)^{2}-3xz+3xz-(3)^{2}\\\\(xz)^{2}-3xz+3xz-(3)^{2}=(xz)^{2}-(3)^{2}

So, the obtained expression is a difference of squares since it matches with the form of the difference of squares.

<h2>D)</h2>

(y^2-xy)(y^2+xy)=(y^{2})^{2}+y^{2}*xy-y^{2}*xy-(xy)^{2} \\\\(y^{2})^{2}+y^{2}*xy-y^{2}*xy-(xy)^{2}=(y^{2})^{2}-(xy)^{2}

So, the obtained expression is a difference of squares since it matches with the form of the difference of squares.

<h2>E)</h2>

(25x-7y)(-7y+25x)=-175xy+(25x)^{2}+49y^{2}-175xy\\\\-175xy+(25x)^{2}+49y^{2}-175xy=(25x)^{2}+49y^{2}-350xy

So, the obtained expression is not a difference of squares

<h2>F)</h2>

(64y^2+x^2)(-x^2+64y^2)=(64y^2+x^2)(64y^2-x^2)\\\\(64y^2+x^2)(64y^2-x^2)=(64y^{2})^{2} -(x^{2}*64y^{2})+(x^{2}*64y^{2})-(x^{2})^{2}\\ \\(64y^{2})^{2} -(x^{2}*64y^{2})+(x^{2}*64y^{2})-(x^{2})^{2}=(64y^{2})^{2}-(x^{2})^{2}

So, the obtained expression is a difference of squares since it matches with the form of the difference of squares.

Hence, the products that result in a difference of squares are:

C) (3+xz)(-3+xz)

D) (y^2-xy)(y^2+xy)

F) (64y^2+x^2)(-x^2+64y^2)

Have a nice day!

5 0
4 years ago
For which of the following would it be appropriate to use positive integers for the domain of the function? Select all that appl
gayaneshka [121]
I think its A,B and E

3 0
3 years ago
Read 2 more answers
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