Which of the following correctly uses absolute value to show the distance between −70 and 15?

1 answer:

7 0

Use the distance formula to get your answer. The distance formula is d=sqrt(x2-x1)^2+(x1-y1)^2 Once you plug your coordinates into it, you'll get your answer.

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Use the Law of Cosines to find the missing angle. In triangle JKL, j=3in., k=4in., and l=2.89., find mJ

slega [8]

Using the law of cosine for Triangle KJL, we can write:

$j^{2} = k^{2} + l^{2}-2(k)(l)cos(J) \\ \\ 
2(k)(l)cos(J)=k^{2} + l^{2}- j^{2} \\ \\ 
cos(J)= \frac{k^{2} + l^{2}- j^{2}}{2(k)(l)}$

Using the values of k,j and l, we can write:

$cos(J)= \frac{ 4^{2} + (2.89)^{2} - 3^{2} }{2(4)(2.89)} \\ \\ 
cos(J)= 0.664 \\ \\ 
J= cos^{-1}(0.664) \\ \\ 
J=48.39$

Rounding to nearest integer, the measure of angle J will be 48 degrees.
So option B gives the correct answer

8 0

3 years ago

Read 2 more answers

Please help me! I need this to complete my math hw

babymother [125]

Answer:

Step-by-step explanation:

You "complete the square" by adding the square of half the x-term coefficient. Here, that is ...

((-2)/2)² = 1 . . . . value added to complete the square

If you want to keep 0 on the right, you must also subtract this value:

x² -2x -36 = 0

x² -2x +1 -36 -1 = 0 . . . . . . add and subtract 1 on the left