Answer:
p(at most one space between) = (4n-6)/(n(n-1))
Step-by-step explanation:
There are n-1 ways the cars can be parked next to each other, and n-2 ways they can be parked with one empty space between. So, the total number of ways the cars can be parked with at most one empty space is ...
(n -1) +(n -2) = 2n-3
The number of ways that 2 cars can be parked in n spaces is ...
(n)(n -1)/2
So, the probability is ...
(2n-3)/((n(n-1)/2) = (4n -6)/(n(n -1))
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If the cars are considered distinguishable and order matters, then the number of ways they can be parked will double. The factor of 2 cancels in the final probability ratio, so the answer remains the same.
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<em>Check</em>
For n=2 or 3, p=1 as you expect.
For n=4, p=5/6, since there is only one of the 6 ways the cars can be parked that has 2 spaces between.
Given the value above, <span>2,000,947 is in the form of STANDARD FORM. To write this in an expanded form, it will be like this: 2, 000, 000 + 947. The exponential form of 2,000,000 is 2 x 10^6. Hope this is the answer that you are looking for. Have a great day!</span>
To determine whether or not an equation is linear or not, we look at the exponets. If the highest exponent on a single variable is one, then the equation is linear.
Answer: x = 14y + 65
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I confused ! I don't get what your trying to say please explain better !
Answer:
8.239x10^-5
so the answer is A
Step-by-step explanation:
trust me
ps. use photomath on phone
