Question

What are the zeros of the quadratic function f(w)=2w^2+7w-4

Answer 1

Answer:f(w)=w^3 + 7/2w^2-4w+c

Step-by-step explanation:

Answer 2

Answer: w = 1/2 and w = -4

Step-by-step explanation:

2w^2+7w-4=0

The quadratic formula is (-b+ - √b^2-4ac)/2a

In this case a=2, b=7, c= -4

(-7+ - √7^2 - 4(2)(-4))/2(2)

(-7+ - √49+32)/4

(-7+ - √81)/4

(-7+9)/4 and (-7-9)/4

2/4        and -16/4    

1/2         and -4