Can anyone help please?

Find an angle in the normal range (0° to 360°, or 0 to 2pi radians) whose terminal side points in the same direction as the term

elena55 [62]

Answer:

A

Step-by-step explanation:

Our angle is -312 degrees, but because angles on the unit circle are always periodic and repeat every 2π or 360°, that means if we add a certain multiple of 360 to -312, we should get an angle with the terminal side pointing in the same direction.

Let's add 360 to -312:

-312 + 360 = 48°

Thus, the answer is A.

6 0

3 years ago

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The first four snowfalls of the year in Gracie's hometown measured 1.6 inches, 2.2 inches, 1.8 inches, and 1.4

frez [133]

1.6+2.2+1.8+1.4 = 7
Have a good day!

5 0

3 years ago

A typical tip in a restaurant is 15% of the total bill. If the bill is $140, what would the typical tip be?

stepladder [879]

15% / 100% = 0.15
$140 x 0.15= $21.00
Typical tip would be $21.00

8 0

3 years ago

Information reference tables the lifespan of a 60-watt lightbulb produced by a company is normally distributed with a mean of 14

irinina [24]

First, we need to standardize the value 1440 and 1465 to be able to work out the z-score

$z= \frac{1440-1450}{8.5}$
$z=-1.77$

$z= \frac{1465-1450}{8.5}$
$z=1.77$

The z-scores are shown in the diagram below

To work out the probability of $-1.77\ \textless \ z\ \textless \ 177$ we can first read on the table, the probability when $P(z\ \textless \ 1.77)=0.9616$ , then we subtract this value from 1, as we are interested in the area to the right of 1.77.

$1-0.9616=0.0384$

Then the area between $z=-1.77$ and $z=1.77$ is $1-2(0.0384)=0.9232$ which is also the probability of lifespan between 1440 and 1465

4 0

4 years ago

The standard deviations of four data sets are shown in the table below. Which

den301095 [7]

Answer:

$s_A = 5.21$

$s_B =4.88$

$s_C = 6.06$

$s_D =3.39$

We need to remember that the deviation is a measure od disperion and for this case is the deviation is larger then we have more spread out the distribution of interest. And largest deviation for this case is from the dataset C so then the answer would be:

D. Data set C

Step-by-step explanation:

For this case the standard deviation can be calculated with the following formula:

$s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And for this case we have the deviations for each dataset are given by:

$s_A = 5.21$

$s_B =4.88$

$s_C = 6.06$

$s_D =3.39$

We need to remember that the deviation is a measure od disperion and for this case is the deviation is larger then we have more spread out the distribution of interest. And largest deviation for this case is from the dataset C so then the answer would be:

D. Data set C

4 0

3 years ago

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