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grigory [225]
3 years ago
10

A right pyramid that is 12 feet tall has a square base whose side length is 5 feet. What is its slant height, what is the length

of its lateral edges?

Mathematics
1 answer:
sveticcg [70]3 years ago
8 0
Check the picture below.

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978.18

Step-by-step explanation:

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Eric is saving $60 every week to buy a new laptop that costs $480. He has already saved $180.
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Answer:

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You saved $200 on a laptop you purchased online. If this was a 25% savings from the original price, find the original cost of the laptop.

13,962 results

Math

You saved $200 on a laptop you purchased online. If this was a 25% savings from the original price, find the original cost of the laptop.

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Solve (x + 1)2 – 4(x + 1) + 2 = 0 using substitution.
solniwko [45]

For this case we have to:

Letu = x + 1

So:

u ^ 2-4u + 2 = 0

We have the solution will be given by:

u = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}

Where:

a = 1\\b = -4\\c = 2

Substituting:

u = \frac {- (- 4) \pm \sqrt {(- 4) ^ 2-4 (1) (2)}} {2 (1)}\\u = \frac {4 \pm \sqrt {16-8}} {2}\\u = \frac {4 \pm \sqrt {8}} {2}\\u = \frac {4 \pm \sqrt {2 ^ 2 * 2}} {2}\\u = \frac {4 \pm2 \sqrt {2}} {2}

The solutions are:

u_ {1} = \frac {4 + 2 \sqrt {2}} {2} = 2 + \sqrt {2}\\u_ {2} = \frac {4-2 \sqrt {2}} {2} = 2- \sqrt {2}

Returning the change:

2+ \sqrt {2} = x_ {1} +1\\x_ {1} = 1 + \sqrt {2}\\2- \sqrt {2} = x_ {2} +1\\x_ {2} = 1- \sqrt {2}

Answer:

x_ {1} = 1 + \sqrt {2}\\x_ {2} = 1- \sqrt {2}

3 0
2 years ago
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What is it called in cubic inch of a cylinder with a height of 4in and a base radius of 5in to the nearest tenths place?
Maru [420]

Answer:

1,256.8in

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Given data

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V=πr²h

Substitute

V=3.142*4²*5

V=3.142 *16*25

V=1,256.8in³

6 0
3 years ago
What is the solution of x + <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7D" id="TexFormula1" title="\frac{1}{5}" alt="\
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Your answer would be A.1
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