we can convert any decimal value to a fraction by simply <u>using in the denominator a power of 10 with as many zeros as there are decimals and lost the dot above</u>, this one has one decimal, so we'll use 1 zero, and lose the dot above.
![\bf 0.\underline{6}\implies \cfrac{06}{1\underline{0}}\implies \cfrac{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\cdot 3}{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\cdot 50}\implies \cfrac{3}{50}](https://tex.z-dn.net/?f=%5Cbf%200.%5Cunderline%7B6%7D%5Cimplies%20%5Ccfrac%7B06%7D%7B1%5Cunderline%7B0%7D%7D%5Cimplies%20%5Ccfrac%7B~~%5Cbegin%7Bmatrix%7D%202%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%5Ccdot%203%7D%7B~~%5Cbegin%7Bmatrix%7D%202%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%5Ccdot%2050%7D%5Cimplies%20%5Ccfrac%7B3%7D%7B50%7D)
Answer:
Yep your very smart
Step-by-step explanation:
32, that’s just 2 to the fifth power so 2*2*2*2*2
Answer:
x = 8
Step-by-step explanation:
A line with "undefined" slope is a vertical line, whose equation is of the form ...
x = constant
In order for the line to go through a point with an x-coordinate of 8, the constant must be 8.
x = 8 . . . . . a vertical line through (8, -3)
Answer:
2^5
Step-by-step explanation:
1^10 = 1 (1*1*1*1*1....)
5^2 = 25 (5*5)
2^5 = 32 (2*2*2*2*2)
3^3 = 27 (3*3*3)
