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3 years ago

-2 (×-5) = 5 (-3×+4) +3 solve please

Mathematics

2 answers:

stealth61 [152]3 years ago

7 0

Give a couple of sec to figure it out.

miss Akunina [59]3 years ago

7 0

-2x + 10 = -15x + 23
-2x = -15x + 13
0 = -13x + 13
-13 = -13x
13 = 13x
x = 1

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In ΔKLM, the measure of ∠M=90°, the measure of ∠L=76°, and LM = 99 feet. Find the length of KL to the nearest tenth of a foot.

hram777 [196]

Answer:

The length of KL is 409.2 foot

Step-by-step explanation:

Firstly, please check attachment for diagrammatic representation.

From the diagram, we can see that we are asked to calculate the value of the hypotenuse KL. Kindly note that the hypotenuse is the longest side of the right-angled triangle and it faces the angle 90 at all times.

Looking at what we have, we can see that we have adjacent and we are asked to calculate hypotenuse.

The trigonometric identity to use here is the Cosine

Cosine = length of adjacent/length of hypotenuse

cos 76 = 99/hypotenuse

hypotenuse = 99/cos76

hypotenuse = 99/0.24192

hypotenuse = 409.22 which is 409.2 to the nearest tenth of a foot

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2 years ago

The plot shown below describes the relationship between student scores on the first exam in a class and their corresponding scor

STALIN [3.7K]

Answer:

you average the scores by adding scores from exam 1 and exam 2 then divide it by 2 to average the exam scores

Step-by-step explanation:

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2 years ago

Find the volume of the prism in terms of y.

pogonyaev

is there a value to y? if not, this is what I got:

Y^2 + 2y + 3

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1 year ago

If the line passing through the points (a, 1) and (−17, 8) is parallel to the line passing through the points (0, 5) and (a + 2,

stellarik [79]

Parallel line means the same slope
（8-1）/(-17-a)=(1-5)/(a+2)
so a is 18

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2 years ago

The curves y = √x and y=(2-x) and the Cartesian axes form two distinct regions in the first quadrant. Find the volumes of rotati

makkiz [27]

Answer:

Step-by-step explanation:

If you graph there would be two different regions. The first one would be

$y = \sqrt{x} \,\,\,\,, 0\leq x \leq 1 \\$

And the second one would be

$y = 2-x \,\,\,\,\,, 1 \leq x \leq 2$ .

If you rotate the first region around the "y" axis you get that

$A_1 = 2\pi \int\limits_{0}^{1} x\sqrt{x} dx = \frac{4\pi}{5} = 2.51$

And if you rotate the second region around the "y" axis you get that

$A_2 = 2\pi \int\limits_{1}^{2} x(2-x) dx = \frac{4\pi}{3} = 4.188$

And the sum would be 2.51+4.188 = 6.698

If you revolve just the outer curve you get

If you rotate the first region around the x axis you get that

$A_1 =\pi \int\limits_{0}^{1} ( \sqrt{x})^2 dx = \frac{\pi}{2} = 1.5708$

And if you rotate the second region around the x axis you get that

$A_2 = \pi \int\limits_{1}^{2} (2-x)^2 dx = \frac{\pi}{3} = 1.0472$

And the sum would be 1.5708+1.0472 = 2.618

7 0

3 years ago