Question

Write an equation in slope-intercept form for the line that passes through point (2, -1) and is parallel to the line described y = (2/3)x - 6

Answer 1

Answer:

$y=\frac{2}{5}x-5$

Step-by-step explanation:

$\\y=\frac{2}{3}x-6$

the line parallel  to this line is

$y=\frac{2}{3}x+k$ ; k ∈ R

the line passes through the point (2,-1)

so,

$-1=\frac{2}{3} (2)+k\\-1=\frac{4}{3} +k\\k=-\frac{7}{3}$

∴the line that passes through point (2, -1) and is parallel to the line described y = (2/3)x - 6 is

$y=\frac{2}{3}x-\frac{7}{3}$