The area under a graph is given by the integral of that function, evaluated in the interval of interest:
![\displaystyle \int_{-3}^2 x^2+4\;dx = \left[\dfrac{x^3}{3}+4x\right]_{-3}^2 = \left[\dfrac{2^3}{3}+4\cdot 2\right]-\left[\dfrac{(-3)^3}{3}+4\cdot(-3)\right] = \left[\dfrac{8}{3}+8\right]-\left[-9-12\right] = \dfrac{32}{3}+21 = \dfrac{95}{3}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cint_%7B-3%7D%5E2%20x%5E2%2B4%5C%3Bdx%20%3D%20%5Cleft%5B%5Cdfrac%7Bx%5E3%7D%7B3%7D%2B4x%5Cright%5D_%7B-3%7D%5E2%20%3D%20%5Cleft%5B%5Cdfrac%7B2%5E3%7D%7B3%7D%2B4%5Ccdot%202%5Cright%5D-%5Cleft%5B%5Cdfrac%7B%28-3%29%5E3%7D%7B3%7D%2B4%5Ccdot%28-3%29%5Cright%5D%20%3D%20%5Cleft%5B%5Cdfrac%7B8%7D%7B3%7D%2B8%5Cright%5D-%5Cleft%5B-9-12%5Cright%5D%20%3D%20%5Cdfrac%7B32%7D%7B3%7D%2B21%20%3D%20%5Cdfrac%7B95%7D%7B3%7D)
Answer:
$24.11
Step-by-step explanation:
Let the cost of the present be c.
Then (3/4)c = $18.33.
To isolate (solve for) c, mult. both sides of this equation by (4/3):
(4/3)(3/4)c = (4/3)($18.33), or
c = $24.11
The following statements are true for a parallelogram that must be a rectangle.
parallelogram with a right angle
parallelogram with congruent diagonals
A Parallelogram is a flat shape with opposite sides parallel and equal in length. Squares, rectangles and rhombuses are all parallelograms but with slight differences.
The height of the triangle is 48/b or 48 over b. That's all I can tell you with the information given.
