Y = 5x is the answer and you can double check by looking at the coordinates
I believe that A is the answer. We can solve this by multiplying 75cm, 65cm and 30cm together. This would give us 146,250.00ml. We can then divide 146,250.00 by 1000 to receive 146.25. We then divide 146.25 by 2 to calculate how many litres there are in half a tank. This would result in 73.125. After that, we multiple 73.125 by the cost of the fuel, which is R20.35. We then receive R 1,480.09375, which can be rounded to R 1,480.10
2000 for RF and IT and EF per month...
30% goes to retirement.....0.30(2000) = 600
IT is 80% of RF.....0.80(600) = 480
remainder goes to EF.......2000 - (600 + 480) = 920
which represents 20% of his salary...
920 = 20% of salary (s)
920 = 0.20s
920/0.20 = s
4600 = s.........he earns 4600 per month <==
Answer:
f(-5) = -16
Step-by-step explanation:
f(x)=2x-6
f(-5) = (2 * -5) -6 = -10 - 6 = -16 ... replace x with -5
The height of the building is 50√3 feet.
Given to us,
Distance between the building and Amar = 50 feet,
Angle between the top of the building and Amar = 60°
We know that the value of tan 60° is √3.
Thus,
![tan\theta=\dfrac{Perpendicular}{Base} \\\\\rm tan\ 60^o =\dfrac{Height\ of\ the\ building}{Distance\ between\ building\ and\ Amar}](https://tex.z-dn.net/?f=tan%5Ctheta%3D%5Cdfrac%7BPerpendicular%7D%7BBase%7D%20%5C%5C%5C%5C%5Crm%20tan%5C%2060%5Eo%20%3D%5Cdfrac%7BHeight%5C%20of%5C%20the%5C%20building%7D%7BDistance%5C%20between%5C%20building%5C%20and%5C%20Amar%7D)
![\sqrt{3} =\dfrac{Height\ of\ the\ building}{50\ feet} \\](https://tex.z-dn.net/?f=%5Csqrt%7B3%7D%20%3D%5Cdfrac%7BHeight%5C%20of%5C%20the%5C%20building%7D%7B50%5C%20feet%7D%20%5C%5C)
![{Height\ of\ the\ building}= {50\ feet}\times\sqrt{3}](https://tex.z-dn.net/?f=%7BHeight%5C%20of%5C%20the%5C%20building%7D%3D%20%7B50%5C%20feet%7D%5Ctimes%5Csqrt%7B3%7D)
Therefore, the height of the building is 50√3 feet.
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