<h3>Add Two-thirds to both sides</h3>
<em><u>Solution:</u></em>
<em><u>Given is:</u></em>
We have to find how this can be solved for "x" in one step
Remember that,
We we add or subtract same number from both sides of a equation, the equation still remains true
Therefore, from given,
Add Two-thirds to both sides
Thus,
Thus, Add Two-thirds to both sides to solve the sum
This kind of exercise can be real drudgery. But it's almost all simple arithmetic, so better you than me. I'll do one of these for you, which will show you how to do the other one.
a). sin · cot / sec
You're supposed to know that [ cotangent = cosine/sine ]
and [ secant = 1/cosine ].
Then the problem becomes
sin · (cos/sin) / (1/cos) = cos²
Aw shucks, I might as well also set up 'b)' for you:
b). cos · csc / tan
You're supposed to know that [ cosecant = 1/sine ]
and [ tangent = sine/cosine ].
Then the problem becomes
cos · (1/sin) / (sin/cos) = (cos/sin)²
Now simply plug in the given values of cos A and sin A .
And may I compliment you on your nail care !
Answer:
121.666666667
Step-by-step explanation:
Answer:
9.12 m^2
Step-by-step explanation:
14*.305=4.27 m
7*.305= 2.135m
multiplied together is 9.12 m^2
I may not be right, but I think it's similar