The height of the kite above the ground is 58.68 ft
Let x be the height of the kite above Chee's hand.
The height of the kite above Chee's hand, the string and the horizontal distance between Chee and the kite form a right angled triangle with hypotenuse side, the length of the string and opposite side the height of the kite above Chee's hand.
Since we have the angle of elevation from her hand to the kite is 29°, and the length of the string is 100 ft.
From trigonometric ratios, we have
tan29° = x/100
So, x = 100tan29°
x = 100 × 0.5543
x = 55.43 ft.
Since Chee's hand is y = 3.25 ft above the ground, the height of the kite above the ground, L = x + y
= 55.43 ft + 3.25 ft
= 58.68 ft to the nearest hundredth of a foot
So, the height of the kite above the ground is 58.68 ft
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You line up the decimal points so that similar place values are lined up. it will be easier to add them.
I hope this helps.....
Explanation:
I took this in 9th grade so I know how to do this kind of stuff
Answer:
a.
b.
Step-by-step explanation:
a. We know that angles in a triangle add up to 180°.
-The right angle triangle in the right triangle has a measure of 90°.
We can therefore equate our angles to 180° and solve for x;
Hence, the angle measure is x=10°
b. Having calculated the value of x from a above as x=10°, we can substitute to find the measures of the two acute angles:
Since, the m∠K is a right angle, it measures 90°
Answer:
There are 9 adults
Step-by-step explanation:
3:5 = x:15
3/5 = x/15
3(15) = 5x
5x = 45
x = 9 adults
3:5 = 9:15
