Answer:
There is 1 way to vote for 0 people. There are 8 ways to vote for 1 person. There are 8⋅7/ 2 ways to vote for 2 people. There are 8⋅7⋅6 /2⋅3 ways to vote for 3 people. There are 8⋅7⋅6⋅5/ 2⋅3⋅4 ways to vote for 4 people. This is all because you can choose people but there are ways you can order the people.
Does this help
We can solve this by using systems of equations.
Let's find our first formula, how much money was made using the tickets.
Here x is how many child tickets we sold and y is how many adult tickets we sold. Now that we have defined that, we can make another formula for the total tickets sold!
since we sold 156 tickets that could be any combination of child and adult tickets.
Let's solve this system. I'm going to use <em>substitution</em> so I'm going to take our second formula and subtract both sides by x to get .
Now I will plug this in the first equation for y to get You plug it in for y to get
From this you can solve for x to get .
Since
There were 99 child tickets and 57 adult tickets.
Answer:
x=5, y=4. (5, 4).
Step-by-step explanation:
2x-3y=-2
4x+y=24
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-2(2x-3y)=-2(-2)
4x+y=24
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-4x+6y=4
4x+y=24
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7y=28
y=28/7
y=4
4x+4=24
4x=24-4
4x=20
x=20/4
x=5
Answer:
Step-by-step explanation:
I got x < 2 for the inequality
Look at the image for more information