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Ber [7]
3 years ago
7

Round 69581. 491337 to the nearest thousand

Mathematics
2 answers:
avanturin [10]3 years ago
6 0

Answer:

7000

Step-by-step explanation:

Vadim26 [7]3 years ago
3 0

Answer:

7000

Step-by-step explanation:

If it is 5 or more, then round up. If it is 4 or less, then round down.

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A cylinder and a come have the same volume. The cylinder has a radius of 2 inches and a height of 3 inches. The cone has radius
MrRissso [65]

Answer: 4in

Step-by-step explanation:

Volume of a cylinder = πR²H

Volume of a cone = 1/3πr²h

πR²H = 1/3πr²h

π is very common so it could be cancelled, so the equation now becomes

R²H = 1/3r²h

3R²H = r²h

Now substitute for the values

h = 3 x 2² x 3

--------------

3²

= 9 x 4/9

= 4in.

Therefore, the height of the cone

h = 4in.

4 0
3 years ago
Find the value of X
vredina [299]

Answer:

x=8

RPS = 36

Step-by-step explanation:

QPS = 180

The two angles that form QPS

QPR + RPS = 180

7x+88 + 3x+12 = 180

Combine like terms

10x+100 =180

Subtract 100 from each side

10x = 180-100

10x = 80

Divide by 10

x =80/10

x = 8

RPS = 3x+12

        = 3(8)+12

         24+12

        36

7 0
3 years ago
Which shows the factored form of x2 – 12x – 45? (x 3)(x – 15) (x – 3)(x – 15) (x 3)(x 15) (x – 3)(x 15).
Aleksandr [31]

The factors of the quadratic equation are (x+3) and (x-15).

<h2 /><h2>Given to us</h2>
  • x^2-12x-45\\

<h3>To find</h3>

The factors of x^2-12x-45\\.

<h3 /><h3>Solution</h3>

x^2-12x-45\\

As we can see in the quadratic equation the value of ac is -45x². therefore, we need to divide -12x into two parts such that their sum must give -12x and their product gives us -45x².

therefore, dividing -12x into -15x and 3x,

x^2-15x+3x-45\\

Taking common out,

x^2-15x+3x-45\\x(x-15)+3(x-15)\\(x+3)(x-15)

Hence, the factors of the quadratic equation are (x+3) and (x-15).

Learn more about quadratic equations:

brainly.com/question/2263981

3 0
2 years ago
Two possible solutions of √11-2x=√x^2+4x+4 are –7 and 1. Which statement is true? A) Only x = –7 is an extraneous solution.
11111nata11111 [884]

Answer:

Option D)Neither solution is extraneous.

Step-by-step explanation:

we have

\sqrt{11-2x}=\sqrt{x^{2}+4x+4}

we know that

two possible solutions are x=-7 and x=1

<u><em>Verify each solution</em></u>

Substitute each value of x in the expression above and interpret the results

1) For x=-7

\sqrt{11-2(-7)}=\sqrt{-7^{2}+4(-7)+4}

\sqrt{25}=\sqrt{25}

5=5 ----> is true

therefore

x=-7 is not a an extraneous solution

2) For x=1

\sqrt{11-2(1)}=\sqrt{1^{2}+4(1)+4}

\sqrt{9}=\sqrt{9}

3=3 ----> is true

therefore

x=1 is not a an extraneous solution

therefore

Neither solution is extraneous

7 0
3 years ago
Read 2 more answers
Simplify ( root 3 + root 7) over 2​
Gala2k [10]

Answer:

5 r o 2 t

Step-by-step explanation:

(√3+√7)²

We know ,[(a+b)²=a²+2ab+b²]

=>(√3+√7)²=(√3)²+2(√3)(√7)+(√7)²

=>(√3+√7)²=3+2√21+7

=>(√3+√7)²=10+2√21

3 0
3 years ago
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