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finlep [7]
3 years ago
5

For a quadrilateral to be a rhombus, the diagonals __ and __.

Mathematics
1 answer:
Fynjy0 [20]3 years ago
7 0
Blank 1= must be congruent
Blank2= must not be perpendicular


Also search up a quadrilateral rhombus see what it looks like then search up the definition of congruent and perpendicular and you’d be able to see for yourself
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The area of a square poster is 31 square inches. find the length of one side of the poster. Explain
kobusy [5.1K]

Answer:

5.57

Step-by-step explanation:

In order to find the are of a square you would use the equation <em>a²</em>. However, since you are finding the length of one side and its a square, you use the equation \sqrt{a}. The area of this square is 31 sq in., so you would replace a with 31. The equation then becomes \sqrt{31}<em>. </em>When out into a calculator, the answer is 5.567764... which rounded up to the nearest hundreth is 5.57.

5 0
3 years ago
100000000000000000000000000000000000000000+53624785326348756348927563482564328965342875634289573264
Arlecino [84]

Answer:

5.3624785e+55

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Which situation about Sam's money could be described using the sum of -2.5 and -10?
Rama09 [41]

Answer:

-12.5  i think

Step-by-step explanation:

4 0
3 years ago
Hey guys I need your help on this!!
kogti [31]

Answer:

Domain: (-∞, ∞) or All Real Numbers

Range: (0, ∞)

Asymptote: y = 0

As x ⇒ -∞, f(x) ⇒ 0

As x ⇒ ∞, f(x) ⇒ ∞

Step-by-step explanation:

The domain is talking about the x values, so where is x defined on this graph? That would be from -∞ to ∞, since the graph goes infinitely in both directions.

The range is from 0 to ∞. This where all values of y are defined.

An asymptote is where the graph cannot cross a certain point/invisible line. A y = 0, this is the case because it is infinitely approaching zero, without actually crossing. At first, I thought that x = 2 would also be an asymptote, but it is not, since it is at more of an angle, and if you graphed it further, you could see that it passes through 2.

The last two questions are somewhat easy. It is basically combining the domain and range. However, I like to label the graph the picture attached to help even more.

As x ⇒ -∞, f(x) ⇒ 0

As x ⇒ ∞, f(x) ⇒ ∞

7 0
2 years ago
Need by TONIGHT please help
igor_vitrenko [27]
Slope = 1/2 :) 
rise over run (rise/run)
so... 2/4 = 1/2 
hope this helps!
7 0
3 years ago
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