Which shows the factored form of x2 – 12x – 45? (x 3)(x – 15) (x – 3)(x – 15) (x 3)(x 15) (x – 3)(x 15).

Mathematics

1 answer:

Aleksandr [31]2 years ago

3 0

The factors of the quadratic equation are (x+3) and (x-15).

<h2 /><h2>Given to us</h2>

$x^2-12x-45\\$

The factors of $x^2-12x-45\\$ .

<h3 /><h3>Solution</h3>

$x^2-12x-45\\$

As we can see in the quadratic equation the value of ac is -45x². therefore, we need to divide -12x into two parts such that their sum must give -12x and their product gives us -45x².

therefore, dividing -12x into -15x and 3x,

$x^2-15x+3x-45\\$

Taking common out,

$x^2-15x+3x-45\\x(x-15)+3(x-15)\\(x+3)(x-15)$

Hence, the factors of the quadratic equation are (x+3) and (x-15).

Learn more about quadratic equations:

brainly.com/question/2263981

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The following system has a solution: x=10, y=-3, z=14

wolverine [178]

<h2>Answer:</h2><h3>False</h3>

<h2>Step-by-step explanation:</h2>

In this problem, we have the following System of Three Equations in Three Variables, so our goal is to determine whether $x=10, \ y=-3, \ z=14$ is the solution to this system, that is, the ordered triple $P(x,y,z)$ where three planes intersect.

The easier way to find the answer is to plug in the x, y and z values in the equations and figure out whether the equations satisfy the solutions. Then:

$First \ Equation: \\ \\ 3(10)+7(-3)-14=-5 \\ \\ It \ satisfies \ the \ first \ equation \\ \\ \\ Second \ Equation: \\ \\ 9(10)-(-3)-4(14)=37 \neq 17 \\ \\ It \ doesn't \ satisfy \ the \ second \ equation$