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sdas [7]
4 years ago
9

Can someone please help me Factor 4x^2 - 81

Mathematics
2 answers:
Oduvanchick [21]4 years ago
6 0
The answer is (2x-9)(2x+9)

4x^2-81
2^2 x^2-9^2
(2x)^2-9^2
(2x-9)(2x+9)
Vsevolod [243]4 years ago
3 0

Answer:

(2x-9)(2x+9)

Step-by-step explanation:

This is a difference of squares because it can be written as (2x)^2-9^2

The formula for factoring a difference of squares is a^2-b^2=(a-b)(a+b)

So replace a with 2x and b with 9 giving us

4x^2-81=(2x-9)(2x+9)

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3 years ago
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3 years ago
How many 7-digit phone numbers are possible, assuming that the first digit can’t be a 0 or a 1? (b) re-solve (a), except now ass
sladkih [1.3K]
A. We are going to form 7 digit numbers from the set {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}

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b.

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Answer:

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3 years ago
A stray dog ate 12 of your muffins. that was 3/10 of all of them! with how many did you start?
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Answer:

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4 0
3 years ago
ANSWER CORRECTLY AND ILL MARK YOU AS THE BRAINLIEST
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Answer:

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Step-by-step explanation:

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3 years ago
Read 2 more answers
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