Can someone please help me Factor 4x^2 - 81
2 answers:
The answer is (2x-9)(2x+9)
4x^2-81
2^2 x^2-9^2
(2x)^2-9^2
(2x-9)(2x+9)
Answer:
(2x-9)(2x+9)
Step-by-step explanation:
This is a difference of squares because it can be written as (2x)^2-9^2
The formula for factoring a difference of squares is a^2-b^2=(a-b)(a+b)
So replace a with 2x and b with 9 giving us
4x^2-81=(2x-9)(2x+9)
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