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Kaylis [27]
3 years ago
8

Priya is hosting a poetry club meeting this week and plans to have fruit punch and cheese for the meeting. She is preparing 8 ou

nces of fruit punch per person and 2 ounces of cheese per person. Including herself, there are 12 people in the club
A package of cheese contains 16 ounces and costs $3.99. A one-gallon jug of fruit punch contains 128 ounces and costs $2.50. Let p represent the number of people in the club, f represents the ounces of fruit punch, c represents the ounces of cheese, and b represents Priya’s budget in dollars
Mathematics
1 answer:
Sveta_85 [38]3 years ago
3 0

Answer:

b= $3.99×2 + $2.50= $10.48

Step-by-step explanation:

We have the following unknowns:

p: number of people in the club

f: ounces of fruit punch

c: ounces of cheese

b: budget in dollars

We know that

p=12

Priya is preparing 8 ounces of fruit punch per person, so:

f= 8×p = 8×12 = 96

We need 96 ounces of fruit punch

Priya is preparing 2 ounces of cheese per person, so:

c= 2×p = 2×12 = 24

We need 24 ounces of cheese

A package of cheese contains 16 ounces and costs $3.99. In order to get all the cheese we need, Priya have to buy 2 packages of cheese.

2×16=32

32>24

A one-gallon jug of fruit punch contains 128 ounces and costs $2.50. Then, Priya have to buy only one gallon jug.

128>96

The budget would be:

b= $3.99×2 + $2.50×1

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Step-by-step explanation:

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Answer:

Given:

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Answer:

Part 1:

The solution set of the system of equations is x = 1, y = 1

Part 2:

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Part 3:

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The difference of the system of equations in Parts 1 and 2 is that they are arranged differently

Step-by-step explanation:

Part 1:

The system of equation is given as follows;

2·x + y = 3...(1)

x = 2·y - 1...(2)

The above system of equations can be written in terms of the variable, y, as follows;

For equation (1), we have;

y = 3 - 2·x

For equation (2), we have;

y = (x + 1)/2

From the attached graph created with Microsoft Excel, we have;

The solution set (the point of intersection) of the system of equations is x = 1, y = 1

To accurately find the common solution, we have;

(x + 1)/2 = 3 - 2·x

x + 1 = 2·(3 - 2·x) = 6 - 4·x

x + 1 = 6 - 4·x

x + 4·x = 6 - 1

5·x = 5

x = 5/5 = 1

x = 1

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Part 2:

y = -2x + 3

x - 2y = -1

∴ x = 2y -1

y = -2(2y -1) + 3

y = -4y + 2 + 3

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y = 1

x = 2y - 1 = 2 - 1 = 1

x = 1

The solution set is x = 1, y = 1

Part 3

The system of equations are similar in terms of their solution

The system of equations are different in terms of their arrangement

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