Answer:41
Step-by-step explanation:
Given equation of the parabola y= -5x^2 -10x -13.
We need to apply formla for x-coordinate of the vertex.
x=-b/2a.
For the given equation we have a=-5 and b=-10.
Plugging values of a and b in formula of x-coordinate of the vertex.
x= -(-10)/2(-5)
x= 10/(-10) = -1.
So, we got x-coordinate of the vertex = -1.
Now, we need to plug x=-1 in given equation to find the y-coordinate of the vertex.
Plugging x=-1 in y= -5x^2 -10x -13, equation we get
y=-5(-1)^2-10(-1)-13.
y= -5(1) +10 -13.
y=-5 +10-13.
y=-18+10.
y=-8.
So, we got y-coordinate of the vertex -8.
Therefore, vertex of the parabola is (-1,-8).
The values which are correct is in the letter A. 0 & 1
Hope this helped!
2c is a factor of both terms.
.. area = 2c(c+1)
Possible expressions for length and width are
1, 2, c, 2c, c+1, 2(c+1), c(c+1), 2c(c+1).
Answer:
it equal 2400
but in an easier and a faster u can just
do 30
x80
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hide number 8 put down the zero then hide the zero in the 80 and multiply normaly
