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Vlad1618 [11]
1 year ago
6

Daniel wrote the following two-column proof for the given information.

Mathematics
1 answer:
Pavel [41]1 year ago
8 0

The information given about the proof does that Daniel made an error on line 2.

<h3>How to illustrate the information?</h3>

Given:

1. AB = 3x +2;  BC = 4x + 8;  AC = 38

2. AB + BC = AC      incorrect (not an angle angle addition postulate)

3. 3x+2 + 4x + 8 = 38         correct

4. 7x + 10 = 38                    correct

5. 7x = 28                           correct

6. x = 4

Daniel made an error on line 2.

Here is the complete question:

Daniel wrote the following two-column proof for the given information. Given: AB = 3x + 2; BC = 4x + 8; AC = 38 Prove: x = 4 Statements Reason 1. AB = 3x + 2; BC = 4x + 8; AC = 38 1. Given 2. AB + BC = AC 2. Angle Addition Postulate 3. 3x + 2 + 4x + 8 = 38 3. Substitution Property of Equality 4. 7x + 10 = 38 4. Combining Like Terms 5. 7x = 28 5. Subtraction Property of Equality 6. x = 4 6. Division Property of Equality On which line, did Daniel make his error? line 2 line 3 line 4 line 5

Learn more about proof on:

brainly.com/question/4134755

#SPJ1

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Answer:

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u substitution

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Let u =(tan^-1 (ln(x)))     du/dx =d/dx  (tan^-1 (ln(x)))

v substitution

                                             Let v = ln x                dv/dx = 1/x

                                              d/dv  (tan ^-1 v)  dv/dx

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cos (tan^-1 (ln(x))  * 1/(ln^2x +1) * 1/x

We know that cos (tan^-1 (a)) = 1/ sqrt(1+a^2)

cos (tan^-1 (ln(x))  * 1/(ln^2x +1) * 1/x

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So basically
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D=233
carlos speed=55
maria speed=50
total time=4.4 hours

so therefor we have to represent
carlos time
maria time
carlos distance
maria dstance

let's say that
remember that whatever carlost drove is 233 minus maria (time and distance)
and since we are solving for maria time and distnace, solve in terms of them
maria time=t
maria distance=d
carlos time=4.4-t
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remember total D=RT
find their seperate equations
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maria
d=50(t)
use them to solve

233-d=55(4.4-t)
subsitute 50(t) for d
233-50t=55(4.4-t)
add 50t to both sides
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distribute using distributiver protperty (a(b+c)=ab+ac)
55(4.4-t)=242-55t
233=242-55t+50t
add like terms
233=242-5t
add 5t to both sides
233+5t=242
subtract 233 from both sides
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