M+7=3+m+4 what is the value of m

Sam and Lou need a total of 1 foot of wire for a science project. Sam's wire measured 7/8- foot long. Do they have enough wire f

Reil [10]

Answer:

Yes, Sam and Lou have enough wire for science project.

Step-by-step explanation:

There is some data missing in the question, so complete question is below:

$Sam\ and\ Lou\ need\ a\ total\ of\ 1\ foot\ of\ wire\ for\ science\ project.$ $Sam's\ wire\ measured\ 8/12\ foot\ long.\ Lou's\ measured\ 7/8-\ foot \ \ long.$ $Do\ they\ have\ enough\ wire\ for\ the\ science\ project?$ $Explain \ your\ reasoning.$

Now, to get that whether they have enough wire for the science project or not.

Measurement of Sam's wire = $\frac{8}{12} \ foot.$

Measurement of Lou's wire = $\frac{7}{8}\ foot.$

Now, adding both the wires of Sam and Lou:

$\frac{8}{12} +\frac{7}{8} \\\\=\frac{16+21}{24} \\\\=\frac{37}{24}$

$=1\frac{13}{24} \ feet.$

As, Sam and Lou need a total of 1 foot of wire for the science project.

And, we see that the Sam's wire and Lou's wire combining gets $1\frac{13}{24}\ feet$ which is more than 1 foot.

Thus, wire they have is enough for science project.

Therefore, yes, Sam and Lou have enough wire for science project.

5 0

3 years ago

At one point the average price of regular unleaded gasoline was $3.41 per gallon. Assume that the standard deviation price per

Aleonysh [2.5K]

Answer:

a) $1-\frac{1}{k^2} =1- \frac{1}{2^2}= 1-0.25 = 0.75$

So we expected about 75% within two deviations from the mean

b) $1-\frac{1}{k^2} =1- \frac{1}{1.5^2}= 1-0.4444 = 0.556$

So we expected about 55.6% within 1.5 deviations from the mean

And the limits are:

$Lower = 3.41 -1.5*0.09 = 3.275$

$Upper = 3.41 +1.5*0.09 = 3.545$

c) We can calculate how many deviations we are within the mean with the limits with this formula:

$z =\frac{x-\mu}{\sigma}$

And using the lower limit we got:

$z = \frac{3.05-3.41}{0.09}=-4$

And with the upper limit we got:

$z = \frac{3.77-3.41}{0.09}=4$

So then the value of k =4 and the percentage is given by:

$1-\frac{1}{k^2} =1- \frac{1}{4^2}= 1-0.0625 = 0.9375$

Step-by-step explanation:

Previous concepts and Data given

$\mu =3.41$ reprsent the population mean

$\sigma=0.09$ represent the population standard deviation

The Chebyshev's Theorem states that for any dataset

• We have at least 75% of all the data within two deviations from the mean.

• We have at least 88.9% of all the data within three deviations from the mean.

• We have at least 93.8% of all the data within four deviations from the mean.

Or in general words "For any set of data (either population or sample) and for any constant k greater than 1, the proportion of the data that must lie within k standard deviations on either side of the mean is at least: $1-\frac{1}{k^2}$

Part a

For this case we can find the percentage required replaincg k =2 and we got:

$1-\frac{1}{k^2} =1- \frac{1}{2^2}= 1-0.25 = 0.75$

So we expected about 75% within two deviations from the mean

Part b

For this case we can find the percentage required replaincg k =2 and we got:

$1-\frac{1}{k^2} =1- \frac{1}{1.5^2}= 1-0.4444 = 0.556$

So we expected about 55.6% within 1.5 deviations from the mean

And the limits are:

$Lower = 3.41 -1.5*0.09 = 3.275$

$Upper = 3.41 +1.5*0.09 = 3.545$

Part c

We can calculate how many deviations we are within the mean with the limits with this formula:

$z =\frac{x-\mu}{\sigma}$

And using the lower limit we got:

$z = \frac{3.05-3.41}{0.09}=-4$

And with the upper limit we got:

$z = \frac{3.77-3.41}{0.09}=4$

So then the value of k =4 and the percentage is given by:

$1-\frac{1}{k^2} =1- \frac{1}{4^2}= 1-0.0625 = 0.9375$

3 0

3 years ago

How do you write 7.7 x 102 in a standard form?

Zinaida [17]

Answer:

is this supposed to say 7.7 x $10^{2}$ ? if so then it's 770 (you move the decimal over 2 places to the right)

6 0

2 years ago

Read 2 more answers

If x varies directly as y and x = 74 when y = 10, find x when y = 4.

Fittoniya [83]

Answer:

The value of x is 21 .

Step-by-step explanation:

We are given that x varies directly as y

--- A

We are given that x = 7 and y = 28

Substitute the values in A

7 = 28k

Now equations becomes :

y = 84

Hence The value of x is 21 .

#Learn more:

Find the value of y for a given value of x, if y varies directly with x.

If y = −252 when x = 84, what is y when x = 74

Step-by-step explanation:

5 0

2 years ago

The image in down there attached

liberstina [14]

Answer:

D

Step-by-step explanation:

For this one, you want to solve it similarly to linear equations.

-13x+11<-24x by adding 24x to both sides becomes 11x<11.

From there, you divide by 11 to isolate x, leaving x<1.

Since the equation has a < symbol (not ≤), the dot is not filled in. X is less than 1, so the arrow goes to the left, making it D.

**This content involves solving and sketching linear inequalities, which you may wish to revise. I'm always happy to help!

4 0

2 years ago