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zloy xaker [14]
3 years ago
14

Please help me it will be greatly appreciated. will give brainliest. question is in attachment.

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
6 0
A) 180-125 =55
B) both bottom angles are 55 and the triangle's angles should add up to 180, so 55 + 55 + x = 180. X = 70
C) CAE and CBD are equal so the bottom angle (that was calculated in A) will be the base acute angle —>55
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Determine which of the following equations, when graphed, intersect at the point (4, 0).
kakasveta [241]

Answer:

Hence, the following equations, when graphed, intersect at the point (4, 0):

x - y = 4 (1)

x + y = 4 (4)

Step-by-step explanation:

<em>" For the graph to intersect at the point (4,0) we mean that when y=0 , x must be equal to 4 or we could say that when x=4 then y=0".</em>

1)

x-y=4

now when y=0 then x=4.

Hence, the graph intersect at the point (4,0).

2)

-x-y=4

When y=0 in the equation then x=-4, Hence the point (4,0) does not lie on the graph of the given function.

3)

2x-y=7

When y=0 then x=7/2.

Hence the graph of the function does not intersect at the point (4,0).

4)

x+y=4

When y=0 then x=4.

Hence the graph of the given function intersect at (4,0).

5)

2x + y = 7

When y=0 then x=7/2.

Hence the graph of the function does not intersect at the point (4,0).

6)

2x + y = -7

When y=0 then x= -7/2.

Hence the graph of the function does not intersect at the point (4,0).


3 0
3 years ago
Graph 18x-6y=-30 indentify the slope and y intercept
CaHeK987 [17]

Answer:

y=3x+5

Step-by-step explanation:

  1. start by putting 18x on the other side of the equation

- to do this you have to subtract, so it will be -18x now

2. now you have -6y=-18x-30

3. now you need to divide -6 by -18 and -30 on the other side to get y by itself

4. this will leave you with y=3x+5 because 6 divided by 18 is three and 30 divided by 6 is five.

I hope this helps!!

5 0
3 years ago
100 points for brainliest!
wariber [46]

Answer:

1) This is because some has their own shape and the commonly used loop is the clothoid loop, e.t.c.

2) This is because researchers found out that it helps ease the passage of the kidney stones.

Step-by-step explanation:

Hope it helps

Thanks.

7 0
3 years ago
Read 2 more answers
Because I already found what they were or you just have to explain how I found it and then on 16 you just have to find it and th
Iteru [2.4K]
11. to find <DAC a triangle will equal to 180° so subtract 100 and 32 from 180° which will give you 48.

12. is 145° not 35° because you add the two angles your given and and subtract from 180° a triangle will ALWAYS equal to 180°

13. To find <BAC a triangle will equal to 180° so subtract 88 and 57 from 180 which will give you 145°

14. is actually the same answers as 11 cause the the angle you need to find will always be the middle number which is the vertex. they both have the same vertex which is <A

15. will be the same as 11 as well.

16. <P will equal to 49.5

17 and 18. <B will actually be 90° if you see that square symbol it actually indicates it's a 90 degree angle. <A will be 48° and to find <C you add all the angles and subtract it by 180 which will give you 42°

hope this helps I'm taking geometry as well keeps practicing and this will get so easy. if you find any mistakes comment ❣

7 0
4 years ago
What are the zeros of the quadratic function f(x) = 6x2 + 12x - 7?<br>​
mina [271]

Answer:

\frac{-6+\sqrt{78} }{6} and \frac{-6-\sqrt{78} }{6}

Step-by-step explanation:

We are asked that what are the zeros of the quadratic function f(x) = 6x² +12x -7.

So, we have to find the roots of the equation, f(x) = 6x² +12x -7 =0 ...... (1)

Since the quadratic function can not be factorized, so we have to apply Sridhar Acharya's formula.

This formula gives if, ax² +bx +c =0, the the two roots of the equation are

\frac{-b+\sqrt{b^{2}-4ac } }{2a} , \frac{-b-\sqrt{b^{2}-4ac } }{2a}

Therefore, in our case 'a' being 6, 'b' being 12 and 'c' being -7, the two roots of the equation (1) will be

\frac{-12+\sqrt{12^{2}-4*6*(-7) } }{2*6},  \frac{-12-\sqrt{12^{2}-4*6*(-7) } }{2*6}

= \frac{-12+\sqrt{312} }{12},\frac{-12-\sqrt{312} }{12}

=\frac{-6+\sqrt{78} }{6} and \frac{-6-\sqrt{78} }{6}

Hence, x= \frac{-6+\sqrt{78} }{6}

and x= \frac{-6-\sqrt{78} }{6}

(Answer)

9 0
4 years ago
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