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zloy xaker [14]
2 years ago
14

Please help me it will be greatly appreciated. will give brainliest. question is in attachment.

Mathematics
1 answer:
Oksi-84 [34.3K]2 years ago
6 0
A) 180-125 =55
B) both bottom angles are 55 and the triangle's angles should add up to 180, so 55 + 55 + x = 180. X = 70
C) CAE and CBD are equal so the bottom angle (that was calculated in A) will be the base acute angle —>55
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15 point help asap marking brainlest!!!!!!!!!!!!!!
ziro4ka [17]

slope =(y2-y1)/(x2-x1)

m=(-1-5)/(1--1)

m=-6/2

m=-3

y-y1=m(x-x1)  point slope form

y-5 = -3 (x--1)

y-5 = -3 (x+1)

distribute

y-5 = -3x -3

add 5 to each side

y = -3x+2

Choice D


4 0
3 years ago
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26.68 is 58% of what number?
LekaFEV [45]
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A right triangle has a base that measure 39 inches and a height that measures 80 inches. What is the length of its hypotenuse?
guajiro [1.7K]
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5 0
3 years ago
Write 4,670,000 in standard form
GrogVix [38]

Step-by-step explanation:

4,670,000

->

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8 0
3 years ago
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Find the volume of the largest rectangular box in the first octant with three faces in the coordinate planes and one vertex in t
Tresset [83]

Answer: The volume of largest rectangular box is 4.5 units.

Step-by-step explanation:

Since we have given that

Volume = xyz

with subject to x+2y+3z=9

So, let z=\dfrac{9-x-2y}{3}

So, Volume becomes,

V=xyz\\\\V=xy(\dfrac{9-x-2y}{3})\\\\V=\dfrac{9xy-x^2y-2xy^2}{3}

Partially derivative wrt x and y we get that

9-2x-2y=0\implies 2x+2y=9\\\\and\\\\9-x-4y=0\implies x+4y=9

By solving these two equations, we get that

x=3,y=\dfrac{3}{2}

So, z=\dfrac{9-x-2y}{3}=\dfrac{9-3-3}{3}=\dfrac{3}{3}=1

So, Volume of largest rectangular box would be

xyz=3\times \dfrac{3}{2}\times 1=\dfrac{9}{2}=4.5

Hence, the volume of largest rectangular box is 4.5 units.

4 0
3 years ago
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