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ahrayia [7]
3 years ago
13

MULTIPLE CHOICE QUESTION

Mathematics
1 answer:
Paha777 [63]3 years ago
3 0

Answer:

i think it will be #3

Step-by-step explanation:

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Find the distance between the points A and B given below.
GalinKa [24]

Answer:

use formula

Step-by-step explanation:

distance between the points A and B=

√((x2-x1)²+(y2-y1)²)

5 0
3 years ago
What is longer: a mile or a kilometer?
kotykmax [81]
A miler is longer than a kilometer.
5 0
3 years ago
The measure of an interior angle of a regular polygon is 120°. What is the measure of each exterior angle? The polygon has how m
Sunny_sXe [5.5K]

Answer:

60°, arms 6

Step-by-step explanation:

let the total arms = n

total generated angles in a regular polygon is = (n-2)×180

now,

(n-2)×180 = 120 n

or, 180n - 360 =120n

or, 60n = 360

or, n = 6

4 0
2 years ago
Look at the table. Make a conjecture about the sum of the first 20 positive even numbers.
Ludmilka [50]
It will be 20*21 based on the pattern in the chart
3 0
3 years ago
Read 2 more answers
Evaluate the expression
larisa86 [58]

Answer:

12-[20-2(6^2\div3\times2^2)]=88

Step-by-step explanation:

So we have the expression:

12-[20-2(6^2\div3\times2^2)]

Recall the order of operations or PEMDAS:

P: Operations within parentheses must be done first. On a side note, do parentheses before brackets.

E: Within the parentheses, if exponents are present, do them before all other operations.

M/D: Multiplication and division next, whichever comes first.

A/S: Addition and subtraction next, whichever comes first.

(Note: This is how the order of operations is traditionally taught and how it was to me. If this is different for you, I do apologize. However, the answer should be the same.)

Thus, we should do the operations inside the parentheses first. Therefore:

12-[20-2(6^2\div3\times2^2)]

The parentheses is:

(6^2\div3\times2^2)

Square the 6 and the 4:

(36\div3\times4)

Do the operations from left to right. 36 divided by 3 is 12. 12 times 4 is 48:

(36\div3\times4)\\=(12\times4)\\=48

Therefore, the original equation is now:

12-[20-2(6^2\div3\times2^2)]\\=12- [20-2(48)]

Multiply with the brackets:

=12-[20-96]

Subtract with the brackets:

=12-[-76]

Two negatives make a positive. Add:

=12+76=88

Therefore:

12-[20-2(6^2\div3\times2^2)]=88

3 0
3 years ago
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