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cestrela7 [59]
2 years ago
12

Find the area of quadrilateral ABCD with vertices A(0, 4), B(4, 1), C(1, -3), and D(-3, 0).

Mathematics
1 answer:
Ivenika [448]2 years ago
4 0

Answer:

To find area of the quadrilateral ABCD, now we have take the vertices A(x1, y1), B(x2, y2), C(x3, y3) and D(x4, y4) of the quadrilateral ABCD in order (counter clockwise direction) and write them column-wise as shown below. Add the diagonal products x1y2, x2y3, x3y4 and x4y1 are shown in the dark arrows.

Step-by-step explanation:

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Alex787 [66]

Answer:

Smaller number: 12

Larger number: 34

Step-by-step explanation:

Let x represent the smaller number.

Let 3x - 2 represent the larger number (The larger number is two less than three times the smaller number, or x)

x + 3x -2 = 46

   Add 3x + x:

4x - 2 = 46

   Add 2 to both sides:

4x = 46 + 2

   Add 46 + 2:

4x = 48

    Divide both sides by 4:

4x/4 = 48/4

x = 12 is the smaller number

Since 12 is the smaller number, and the sum of the two numbers is 46, than the larger number must be 34.

I hope this helped you. If it did, please consider, rating, pressing thanks and/or giving my answer 'Brainliest.' Have a great day! :)

6 0
3 years ago
The general form of the equation of a circle is Ax2 By2 Cx Dy E = 0, where A = B 0. If the circle has a radius of 3 units and th
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Answer:

Step-by-step explanation:

a)

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