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2 years ago

12

Find the area of quadrilateral ABCD with vertices A(0, 4), B(4, 1), C(1, -3), and D(-3, 0).

1 answer:

Ivenika [448]2 years ago

4 0

Answer:

To find area of the quadrilateral ABCD, now we have take the vertices A(x1, y1), B(x2, y2), C(x3, y3) and D(x4, y4) of the quadrilateral ABCD in order (counter clockwise direction) and write them column-wise as shown below. Add the diagonal products x1y2, x2y3, x3y4 and x4y1 are shown in the dark arrows.

Step-by-step explanation:

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$y =f(x) = - 2x + 4$

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$f( - 4) = - 2( - 4) + 4$

$f( - 4) = 8 + 4$

$f( - 4) = 12$

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$f(0) = - 2(0) + 4$

$f(0) = 0 + 4$

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$f(5) = - 2(5) + 4$

$f(5) = - 10 + 4$

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Range = { 12 , 4 , -6 }

Thus the correct answer is (( A )) .

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