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Arlecino [84]
3 years ago
12

Find the distance between the two points rounding to the nearest tenth (if necessary (3,-4) and (9,4)

Mathematics
1 answer:
GarryVolchara [31]3 years ago
7 0

Answer:

The distance between the two points is 10 units.

Step-by-step explanation:

Given that,

First point = (3,-4)

Second point = (9,4)

To find,

The distance between the two points.

Solution,

The distance between two points (x₁,y₁) and (x₂,y₂) is given by distance formula i.e.

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Put all the values,

D=\sqrt{(9-3)^2+(4-(-4))^2}\\\\D=\sqrt{36+64}\\\\D=10

So, the distance between two given points is 10 units.

Reference,

brainly.com/question/3085146

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The length of a rectangle is 10 in. What is the perimeter of the rectangle if the width is 7 in. less than the length? a. 26 in.
exis [7]

Answer:

Option A P=26\ in

Step-by-step explanation:

we know that

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substitute the value of L in the equation A

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3 years ago
How do you find the sale's price for a sneaker that is normally sold at $150 but is now being sold at a 23% discount?
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3 years ago
A marketing firm wants to estimate how much root beer the average teenager drinks per year. A previous study found a standard de
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Answer:

At least 832 teenargers must be interviewed.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

How many teenagers must the firm interview in order to have a margin of error of at most 0.1 liter when constructing a 99% confidence interval

At least n teenargers must be interviewed.

n is found when M = 0.1.

We have that \sigma = 1.12

So

M = z*\frac{\sigma}{\sqrt{n}}

0.1 = 2.575*\frac{1.12}{\sqrt{n}}

0.1\sqrt{n} = 2.575*1.12

\sqrt{n} = \frac{2.575*1.12}{0.1}

(\sqrt{n})^{2} = (\frac{2.575*1.12}{0.1})^{2}

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Rounding up

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