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Arlecino [84]
3 years ago
12

Find the distance between the two points rounding to the nearest tenth (if necessary (3,-4) and (9,4)

Mathematics
1 answer:
GarryVolchara [31]3 years ago
7 0

Answer:

The distance between the two points is 10 units.

Step-by-step explanation:

Given that,

First point = (3,-4)

Second point = (9,4)

To find,

The distance between the two points.

Solution,

The distance between two points (x₁,y₁) and (x₂,y₂) is given by distance formula i.e.

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Put all the values,

D=\sqrt{(9-3)^2+(4-(-4))^2}\\\\D=\sqrt{36+64}\\\\D=10

So, the distance between two given points is 10 units.

Reference,

brainly.com/question/3085146

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Could -free, automatic faucets actually be housing more bacteris than the old fashioned, manual kind The concern is that decreas
Volgvan

Answer:

Not enough evidence to reject Null hypothesis

Step-by-step explanation:

Solution:-

- A comparative study for bacterial growth in manual and electronic faucets is made.

- It is observed that there is a higher growth in electronic faucets due to slower flow rates, i.e electronic faucets are not thoroughly flushed; hence, giving more resident time for the scaled bacteria to grow.

- It is known that 15% of cultures from older faucets were tested positive for the Legionella bacteria.

- A study at John Hopkins was conducted on a sample n = 20 electronic faucets with the probability of bacteria growing in a faucet is 0.15.

- We will conduct a hypothesis for at-least half proportion of electronic faucets have cultured bacteria.

- State the hypothesis for the proportion of electronic faucets culturing Legionella bacteria:

        Null Hypothesis:  P = 0.15

        Alternate hypothesis: P > 0.15    

- To determine the test statistics for the study conducted at John hopkins. We had a sample size of n = 20, and the probability for a bacteria to grow in a faucet is 0.15.

- Denote random variable, X: The number of electronic faucets culturing Legionella bacteria.

- Since, the probability for a bacteria to grow in a faucet is independent for each new faucet. We will assume the RV " X " to follow binomial distribution with probability of success 0.15:

                      X ~ Bin ( 20 , 0.15 )                  

- We are to determine that at-least half of the sample is subjected to the said bacteria. This is the probability of P ( X ≥ 10 ).

- The pmf for a binomially distributed random variable X is given below:

                     P ( X = r ) = n_C__r * ( p(success) )^r * ( p (fail) )^(^n^-^r^)

Where,

            p ( success ) = 0.15

            p ( fail ) = 1 - p ( success ) = 1 - 0.15 = 0.85

- Use the pmf to determine the required test statistics:

P ( X \geq 10 ) = 1 - P ( X \leq  9 )\\\\P ( X \geq 10 ) = 1 - [ (0.85)^2^0 + 20*(0.15)*(0.85)^1^9 + 20_C_2 (0.15)^2*(0.85)^1^8 +\\\\ 20_C_3 (0.15)^3*(0.85)^1^7 + 20_C_4 (0.15)^4*(0.85)^1^6 + 20_C_5 (0.15)^5*(0.85)^1^5+\\\\ 20_C_6 (0.15)^6*(0.85)^1^4 + 20_C_7 (0.15)^7*(0.85)^1^3 + 20_C_8 (0.15)^8*(0.85)^1^2 + \\\\ 20_C_9 (0.15)^9*(0.85)^1^1\\\\\\P ( X \geq 10 ) = 1 - [  0.03875 + 0.13679 + 0.22933 + 0.24282 + 0.18212 + 0.10284 + \\\\ 0.04537 + 0.01601 + 0.00459 + 0.00108 ]\\\\

P ( X \geq 10 ) = 1 - [ 0.997 ] = 0.003

- The probability that 10 or more electronic faucets is found to have Legionella bacteria growing is 0.003              

- The test proportion of 10 and more electronic faucets have culturing bacteria is p = 0.003.

- Assuming normality of the population, the Z-statistics would be:

                  Z-test = \frac{ (p - P) \sqrt{n} }{\sqrt{P*(1 - P )} } \\\\Z-test = \frac{ (0.003 - 0.15) \sqrt{20} }{\sqrt{0.15*(0.85)} } \\\\Z-test = -1.84109

- If we were to test the claim to 90% level of confidence:

                  significance level (α) = 1 - CI = 1 - 0.9 = 0.1

- The rejection region Z-critical is defined by a right-tail:

                 Z-critical \geq Z_\alpha \geq Z_0_._2\\\\Z-critical \geq 1.28    

- Compare the test statistics with the rejection criteria defined by the Z-critical:

                Z-test < Z-critical

                -1.84 < 1.28

Conclusion:

There is not enough evidence that the probability of Legionella bacteria growing in electronic faucets is greater than 15%.

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