Question

Th term of a seq uence is n(n-4) /n+3 Work out the sum of the 1st and 6th terms.

Answer 1

Answer:

7/12

Step-by-step explanation:

The nth term Tₙ = n(n-4) /n+3.

The 1st term T₁ = 1(1 - 4)/(1 + 3) = -3/4

The 6th term T₆ = 6(6 - 4)/(6 + 3) = 6(2)/9 = 2(2)/3 = 4/3

So,  the sum of the 1st and 6th terms is T₁ + T₆ = -3/4 + 4/3

= (-9 + 16)/12

= 7/12