Th term of a seq uence is n(n-4) /n+3 Work out the sum of the 1st and 6th terms.
1 answer:
Answer:
7/12
Step-by-step explanation:
The nth term Tₙ = n(n-4) /n+3.
The 1st term T₁ = 1(1 - 4)/(1 + 3) = -3/4
The 6th term T₆ = 6(6 - 4)/(6 + 3) = 6(2)/9 = 2(2)/3 = 4/3
So, the sum of the 1st and 6th terms is T₁ + T₆ = -3/4 + 4/3
= (-9 + 16)/12
= 7/12
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