Answer:
12 is the horizontal distance and 16 is the vertical distance
Answer:8.5 is x but there is an extra 1
Step-by-step explanation:18x8.5=153+8=162 with an extra one is 162
Answer:
<u>Perimeter</u>:
= 58 m (approximate)
= 58.2066 or 58.21 m (exact)
<u>Area:</u>
= 208 m² (approximate)
= 210.0006 or 210 m² (exact)
Step-by-step explanation:
Given the following dimensions of a rectangle:
length (L) =
meters
width (W) =
meters
The formula for solving the perimeter of a rectangle is:
P = 2(L + W) or 2L + 2W
The formula for solving the area of a rectangle is:
A = L × W
<h2>Approximate Forms:</h2>
In order to determine the approximate perimeter, we must determine the perfect square that is close to the given dimensions.
13² = 169
14² = 196
15² = 225
16² = 256
Among the perfect squares provided, 16² = 256 is close to 252 (inside the given radical for the length), and 13² = 169 (inside the given radical for the width). We can use these values to approximate the perimeter and the area of the rectangle.
P = 2(L + W)
P = 2(13 + 16)
P = 58 m (approximate)
A = L × W
A = 13 × 16
A = 208 m² (approximate)
<h2>Exact Forms:</h2>
L =
meters = 15.8745 meters
W =
meters = 13.2288 meters
P = 2(L + W)
P = 2(15.8745 + 13.2288)
P = 2(29.1033)
P = 58.2066 or 58.21 m
A = L × W
A = 15.8745 × 13.2288
A = 210.0006 or 210 m²
The required range of the data is 24mm
The range of data is the difference between the largest value and the least value in a set of data.
Since we are not given the range of data. Let's assume we gave the following data:
34mm, 30mm, 20mm, 44mm, 31mm
From the data
Highest measurement = 44mm
Least measurement = 20mm
Find the range
Range = Highest measurement - Least measurement
Range = 44mm - 20mm
Range = 24mm
Hence the required range of data is 24mm
<em>NB: The concept can be applied to any set of data given for other measurements in (b) and (c)</em>
<em>Learn more here: brainly.com/question/1786006</em>
Answer:
from the working in the photo